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Vadim26 [7]
3 years ago
9

Earth's gravitational pull just got threetimes stronger! what happens to your weight/

Physics
1 answer:
OLga [1]3 years ago
8 0
Hold on and let's discuss this realistically.

Because of gravity, there are two forces between the Earth and me. One draws me toward the Earth. The strength of that force is what I call my "weight". The other force draws the Earth toward me, and has the same strength.

The strength of these forces depends on the masses of the Earth and me. If the strength just tripled, that means that at least one of us just picked up a lot more mass. If the Earth suddenly became three times as massive, then the weight of everything and everybody on it would suddenly triple, and I'm pretty sure it would be the end of all of us before too long.

If it was only MY mass that suddenly tripled, that would mean that I had gone tearing through my house and the neighbour's house, eating everything in sight including the 2 couches, 3 dogs, and 6 TVs. Naturally, just as you would expect, my weight changed from 207 to 621, and my skin is stretched really tight.
ooohhh
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Please help me do this problem
Digiron [165]

Answer:

i) acceleration from B to D is 0, because the velocity is constant (stays the same)

ii) whatever units of distathat might be, we can calculate the number:

for 4 time-steps (2 to 6) the velocity is 6 per time step, that makes 24 distance units in these 4 time steps. it's the same the area underneath the graph.

there is also the vertical line from 0 to 2. we can calculate that distance like the area of a triangle with 2*6 / 2 = 6

the total distance from 0 to D is therefore 30

4 0
3 years ago
Question 6
Kisachek [45]
6. gas

7. liquid

8. gas

9. does not change

10. boiling point
7 0
3 years ago
PLEAASE HELP KE WITH THESE THREE YOULL GET POINTS
lozanna [386]

Answer:

  1. 0.0121
  2. 19.8387
  3. 2.2632

Explanation:

1.

\mathrm{The\:solution\:for\:Long\:Division\:of}\:\frac{0.01223}{1.01}\:\\\mathrm{is}\:0.0121

2.

\frac{\begin{matrix}\space\space&\textbf{\space\space}&\space\space&\space\space&\space\space&4&9&10\\ \space\space&\textbf{1}&9&.&8&\linethrough{5}&\linethrough{10}&\linethrough{0}\\ -&\textbf{0}&0&.&0&1&1&3\end{matrix}}{\begin{matrix}\space\space&\textbf{1}&9&.&8&3&8&7\end{matrix}}\\\\=19.8387

3.

0.1886\times 12\\\\Multiply\:without\:the\:decimal\:points,\:then\:put\:the\:decimal\:point\:in\:the\:answer\\1886\times\:12=22632\\\\0.1886\mathrm{\:has\:}4\mathrm{\:decimal\:places}\\12\mathrm{\:has\:}0\mathrm{\:decimal\:places}\\\\\mathrm{Therefore,\:the\:answer\:has\:}4\mathrm{\:decimal\:places}\\\\=2.2632

3 0
3 years ago
Which is the best description of inertia? Inertia is
valentinak56 [21]

Answer:

The best description of inertia is an objects velocity

8 0
4 years ago
Which of the following statements are true of the horizontal motion of projectiles? List all that apply.a. A projectile does not
r-ruslan [8.4K]

Answer:

d. A projectile with a horizontal component of motion will have a constant horizontal velocity.

f. The horizontal velocity of a projectile is unaffected by the vertical velocity; these two components of motion are independent of each other.

g. The horizontal displacement of a projectile is dependent upon the time of flight and the initial horizontal velocity.

h. The final horizontal velocity of a projectile is always equal to the initial horizontal velocity.

Explanation:

When we are dealing with parabolic motion, the x-component of the velocity remains the same (hence, in the case of the horizontal component, the acceleration will always be zero), <u>while the y-component always change because it is affected by the acceleration due gravity that acts verticaly.</u>

On the other hand, the horizontal displacement x of the projectile is mathematically expressed as:

x=V_{ox} t  

Where:  

V_{ox} is the projectile's horizontal component of the initial velocity  

t is the time the parabolic motion lasts

This means <u>the projectile's horizontal displacement is directly proportional to the horizontal component of the initial velocity and the total time the projectile describes the parabolic motion</u>.

Of course, all of this considerations are assuming this is an ideal parabolic path and there is no air resistance.

5 0
4 years ago
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