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Phantasy [73]
3 years ago
15

A car has negative acceleration. What information can you infer from this? (4 points) a The car is speeding up and changing its

direction. b The car is speeding up in the same direction. c The car is changing its direction. d The car is slowing down.
Physics
1 answer:
mario62 [17]3 years ago
5 0

Answer:

D. The car is slowing down.

Explanation:

When a car slows down, the acceleration is in the opposite direction as the velocity. With that being said, the car would have negative acceleration.

hope this helps!! p.s. i really need brainliest :)

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zanele has a mass of 40kg and is sitting inside a 20kg cart .zanele's friends pull a cart with a force of 500N at an angle of 20
Dmitriy789 [7]

The net horizontal force acting on the cart is 169.85 N.

The change in the carts momentum is 5,000 Ns.

The net horizontal force on Zanele is same as the net horizontal force on the cart.

If angle between the 500N force and the horizontal is decreased, the final velocity of the cart increases.

The given parameters:

  • Mass of zanele, m1 = 40 kg
  • Mass of the cart, m2 = 20 kg
  • Applied force, F = 500 N, at angle 20 degrees
  • Frictional force on the cart, Ff = 300 N
  • Time, t = 10 s

<h3>Net horizontal force on the cart;</h3>
  • The net horizontal force acting on the cart is calculated as follows;

F_{net} = F - F_f\\\\F_{net} = 500 \times cos(20) - 300\\\\F_{net} = 169.85 \ N

<h3>Change in momentum;</h3>
  • The change in the carts momentum at the given time of applied force is calculated as follows;

\Delta mv = Ft  \\\\\Delta mv = 500 \times 10= 5,000 \ Ns

The net horizontal force on Zanele is same as the net horizontal force on the cart.

<h3>The final velocity of the cart;</h3>
  • When the angle decreases the cart's final velocity would be affected  as follows;

F_{net} = F - F_f\\\\F_{net} = \frac{mv}{t} \\\\\frac{mv}{t} =  F - F_f\\\\  \frac{mv}{t} =  Fcos(\theta) - F_f\\\\let \ \theta  = 0^0\\\\\frac{mv}{t} =500 \times cos(0) - 300\\\\\frac{mv}{t} = 200\\\\v = \frac{200 t}{m} \\\\when \ \theta = 20^0\\\\\frac{mv}{t} =500 \times cos(20) - 300\\\\\frac{mv}{t} = 169.85\\\\v = \frac{169.85t}{m}

Thus, if angle between the 500N force and the horizontal is decreased, the final velocity of the cart increases.

Learn more about net horizontal force here: brainly.com/question/21684583

5 0
3 years ago
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