Question

WHOEVER GETS THIS RIGHT WILL HAVE 60+ POINTS (MATH) NO BAD ANSWERS ORELSE REPORTING

Answer 1

Answer:

Part A) The system of equations is

$2x+y=10$

$2x+3y=22$

Part B) The number of minutes it takes you to jog around the park is $6$ mins

Explanation:

Part A) Write a system of linear equations

Let $x$ ----> the number of minutes it takes you to jog around the block

Let $y$ ----> the number of minutes it takes you to jog around the park

we know that $2x+y=10$ ----> equation A

and $2x+3y=22$ ----> equation B

Part B) How long does it take you to jog around the park?

Multiply equation A by $-1$ both sides

$-1(2x+y)=-10$ ----> $-2x-y=-10$ ----> equation C

Adds equation B and equation C

$2x+3y=22$

$-2x-y=-10$

____________

$3y-y=22-10$

$2y=12$

$y=6$ minutes

Find the value of $x$

$2x+(6)=10$

$2x=10-6$

$x=4/2=2$ minutes

Credit:

(This answer was originally made by calculista. All credit goes to them.)

Answer 2

9514 1404 393

Answer:

  a. 2x +y = 10; 2x +3y = 22

  b. 6 minutes

Step-by-step explanation:

a) The problem statement tells you that ...

  x = minutes around the block

  y = minutes around the park

  2x +y = 10 . . . . twice around the block and once around the park: 10 min

  2x +3y = 22 . . . twice around the block and 3 times around the park: 22 min

__

b) Subtracting the first equation from the second gives ...

  (2x +3y) -(2x +y) = (22) -(10)

  2y = 12 . . . . . . . . simplify

  y = 6 . . . . . . . . . divide by 2

It takes you 6 minutes to jog around the park.