Answer:
loses electrons and loses potential energy.
Explanation:
A reducing agent looses electrons in an oxidation-reduction reaction. Oxidation is defined as the loss of electrons.
Reducing agents are oxidized in an oxidation-reduction reaction. When a specie looses electrons, it also looses energy. Hence the answer given above.
Because the molecular solutions have low melting and boiling points, and do not conduct electricity.
Answer:
H2SO4 + 2NaOH ==> Na2SO4 + 2H2O
Explanation:
Answer:
Mn^2+(aq) + 4H2O(l) + 5[VO2]^+(aq) + 10H^+(aq) ---------->MnO4^-(aq) + 8H^+(aq) + 5[VO]^2+(aq) + 5H2O(l)
Explanation:
Oxidation half equation:
Mn^2+(aq) + 4H2O(l) ------------> MnO4^-(aq) + 8H^+(aq) + 5e
Reduction half equation:
5[VO2]^+(aq) + 10H^+(aq) + 5e --------> 5[VO]^2+(aq) + 5H2O(l)
Overall redox reaction equation:
Mn^2+(aq) + 4H2O(l) + 5[VO2]^+(aq) + 10H^+(aq) ---------->MnO4^-(aq) + 8H^+(aq) + 5[VO]^2+(aq) + 5H2O(l)
I dont get it someone please help