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2 years ago

15

Kiran shops for books during a 20% off sale. Write an equation that relates the sale price, s, to the original price p.

1 answer:

NemiM [27]2 years ago

4 0

Answer:

s=p*.2

Step-by-step explanation:

.2 is 20 percent in decimal form

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10-11d>-5d-4 show step by step

aliya0001 [1]

The first step for solving this is to move the variable to the left side and then change its sign.
10 - 11d + 5d > - 4
Now move the constant to the right side and change its sign.
-11d + 5d > -4 - 10
Collect the terms with a d variable.
-6d > -4 - 10
Calculate the difference on the right side.
-6d > -14
Lastly,, divide both sides of the inequality by -6 and flip the inequality sign to find your final answer.
d < $\frac{7}{3}$
Let me know if you have any further questions.
:)

4 0

2 years ago

A bag contains 6 red apples and 5 yellow apples. 3 apples are selected at random. Find the probability of selecting 1 red apple

tester [92]

Answer: The required probability of selecting 1 red apple and 2 yellow apples is 36.36%.

Step-by-step explanation: We are given that a bag contains 6 red apples and 5 yellow apples out of which 3 apples are selected at random.

We are to find the probability of selecting 1 red apple and 2 yellow apples.

Let S denote the sample space for selecting 3 apples from the bag and let A denote the event of selecting 1 red apple and 2 yellow apples.

Then, we have

$n(S)=^{6+5}C_3=^{11}C_3=\dfrac{11!}{3!(11-3)!}=\dfrac{11\times10\times9\times8!}{3\times2\times1\times8!}=165,\\\\\\n(A)\\\\\\=^6C_1\times^5C_2\\\\\\=\dfrac{6!}{1!(6-1)!}\times\dfrac{5!}{2!(5-2)!}\\\\\\=\dfrac{6\times5!}{1\times5!}\times\dfrac{5\times4\times3!}{2\times1\times3!}\\\\\\=6\times5\times2\\\\=60.$

Therefore, the probability of event A is given by

$P(A)=\dfrac{n(A)}{n(S)}=\dfrac{60}{165}=\dfrac{4}{11}\times100\%=36.36\%.$

Thus, the required probability of selecting 1 red apple and 2 yellow apples is 36.36%.

4 0

2 years ago

Which ordered pairs are solutions to the inequality 3x-4y>5

Sloan [31]

Note: you did not provide the answer options, so I am, in general, solving this query to solve your concept, which anyways would clear your concept.

Answer:

Please check the explanation.

Step-by-step explanation:

Given the inequality

$3x-4y>5$

All we need is to find any random value of 'x' and then solve the inequality.

For example, putting x=3

$3\left(3\right)-4y>5$

$9-4y>5$

$-4y>-4$

$\mathrm{Multiply\:both\:sides\:by\:-1\:\left(reverse\:the\:inequality\right)}$

$\left(-4y\right)\left(-1\right)$

$4y$

$\mathrm{Divide\:both\:sides\:by\:}4$

$\frac{4y}{4}$

$y$

So, at x = 3, the calculation shows that the value of y must be less

than 1 i.e. y<1 in order to be the solution.

Let us take the random y value that is less than 1.

As y=0.9 < 1

so putting y=0.9 in the inequality

$3\left(3\right)-4\left(0.9\right)$

$=9-3.6$

$=5.4$

As 5.4 > 5

Means at x=3, and y=0.9, the inequality is satisfied.

Thus, (3, 0.9) is one of the many ordered pairs solutions to the inequality 3x-4y>5.

6 0

2 years ago

At what values of x does f(x) = x^3 - 2x^2 -4x+1 satisfy the mean value theorwm on [0,1]

denis-greek [22]

Answer:

x=1/3

Step-by-step explanation:

A function f is given as

$f(x) = x^3-2x^2-4x+1$ in the interval [0,1]

This function f being an algebraic polynomial is continuous in the interval [0,1] and also f is differntiable in the open interval (0,1)

Hence mean value theorem applies for f in the given interval

$f(1) = 1-2-4+1 = -4\\f(0) = 1$

The value

$\frac{f(1)-f(0)}{1-0} =\frac{-4-1}{1} =-5$

Find derivative for f

$f'(x) = 3x^2-4x-4$

Equate this to -5 to check mean value theorem

$3x^2-4x-4=-5\\3x^2-4x+1=0\\\\(x-1)(3x-1) =0\\x= 1/3 : x = 1$

We find that 1/3 lies inside the interval (0,1)

4 0

2 years ago

⅒ (to decimal)<br><br>A. 0.1<br>B. 0.53<br>C. 0.10

nydimaria [60]

⅒ (to decimal)

A. 0.1

7 0

2 years ago