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Nataly_w [17]
2 years ago
11

What is advantage of using single fixed pulley although it doesnot multiply force?​

Chemistry
2 answers:
luda_lava [24]2 years ago
4 0

A single fixed pulley is used to lift load by changing the direction of the lifting force. Even though a single fixed pulley has no mechanical gain in that, the effort applied is greater than the load, it is preferred in use since you do not have to pull or push the pulley up and down.

Zolol [24]2 years ago
4 0

Answer:

A single fixed pulley is used to lift load by changing the direction of the lifting force. Even though a single fixed pulley has no mechanical gain in that, the effort applied is greater than the load, it is preferred in use since you do not have to pull or push the pulley up and down.

Explanation:

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If 12.6 grams of iron (III) oxide reacts with 9.65 grams of carbon monoxide to produce 7.23 g of pure iron, what are the theoret
Mariana [72]
The balanced equation is Fe₂O₃ + 3 CO = 2 Fe + 3 CO₂.
Next step is to convert everything to moles.
12.6g Fe₂O₃ x (1 mol Fe₂O₃ / 159.7g Fe₂O₃) = 0.07890 mol Fe₂O₃ 
9.65g CO x (1 mol CO / 28.01g CO) = 0.3445 mol CO
The third step is to determine the limiting and excess reactants.
0.07890 mol Fe₂O₃ x (3 mol CO/1 mol Fe₂O₃) = 0.2367 mol CO
Therefore Fe₂O₃ is the limiting reagent while CO is in excess.

0.07890 mol Fe x (2 mol Fe(s) / 1 mol Fe₂O₃) = 0.1578 mol Fe(s) 
0.1578 mol Fe x (55.84g Fe / mole Fe) = 8.812g Fe is the theoretical yield
%yield = (7.23g / 8.812g) x 100% = 82.0% is the percent yield
3 0
3 years ago
An element has an atomic mass of 69.66 amu. It has two
marin [14]

Answer: 63.26%

Explanation:

If we let the abundance of the first isotope be x, then:

69.66=(68.9255)(x)+(70.9247)(1-x)\\69.66=68.9255x+70.9247-70.9247x\\-1.2647=-1.9992x\\x=\frac{-1.2647}{-1.9992} \approx 0.6326

Which is equal to <u>63.26%</u>

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You put steel wool in a water bottle and put a balloon on top. The balloon starts to expand. Which type of property are you test
Irina18 [472]
It’s c, physical to oxidation
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Given w = 0, an endothermic reaction has the following.
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Calculate the specific heat of the substance if 373 J is required to raise the temperature of a 312 gram sample by 25°C?
I am Lyosha [343]

Explanation:

Q = 373J

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Q = mc∆∅

373 = 312(x)(25)

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x = 373/7800

x = 0.0478J/(g°C)

4 0
3 years ago
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