Answer:
b. Add NO gas
Explanation:
According with Le Chatelier´s principle, when a reactant is added the equilibrium is displaced to the product(s), to achieve the equilibrium again. Therefore, if NO is added in the reaction, it will be produced more of NO2(g).
Answer:
≈ 708
Explanation
Here we have equation as:
4 Al + 3 O₂ → 2 Al₂O₃
As we know:
No of moles = Mass/ Molar mass
Here, Mass is 375 g and Molar mass is 27 gms, so no. of moles of Al will be:
=375 g /27 g/mol
= 13.889 mol
About mole ratio, we can see that for 4 moles of Al , 2 moles of Al2O3 are formed, so for 13.889 moles of Al, 13.889 mol ÷ 2 =6.944 moles of Al₂O₃ will be formed.
As we know:
Mass= No of moles/Molar mass
Mass of Al₂O₃ = 6.944 mol × 102 g/mol
= 708.288 g
Hope it helps!
One of the most convenient ways of finding or calculating for the
midpoint of the line segment is to get the average of the coordinates of the
points.
Average of abscissa = (0 + 0) / 2 = 0
Average of ordinate = (0 + 15) / 2 = 7.5
Hence, the midpoint of the line segment is equal to (0, 15/2).
The value of the y-intercept is 15/2.
Answer:
Answer) The first box represent the budding type of asexual reproduction . In budding due to the cell divison at the particular place in the organism , new individual will produced.
Second picture represent the budding in hydra. Budding is also a asexual reproduction.
Third type of asexual reproduction is found in plants it is vegetative reproduction.
Fourth is Binary fission . This is also a type of asexual reproduction, in which nucleus dicied into two new daughter cell via mitosis.Explanation:
