describe how 250 cm³ of 0.2 mol/dm³ H2SO4 could be prepared from 150 cm³ of 1.0mol/dm³ stock solution of the acid
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First of all the ethylamine is base so will be react with water to take the proton from the water (H⁺) , because water is amphoteric will react with bases as acid and acids as a base, so the water in this case will react as an acid and will gives the proton to the base.
In the picture you may see the chemical equation and the structure of the products.
Answer:
Explanation:
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In this case, for the dissociation of the sodium hydroxide into sodium and hydroxyl ions we have:
Which is a 100% dissociation as sodium hydroxide is a strong base, therefore, the concentration of the hydroxyl ions are 1.0x10⁻⁹. For that reason, the pOH could be computed as:
Finally, from the definition of pH, we have:
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