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2 years ago

describe how 250 cm³ of 0.2 mol/dm³ H2SO4 could be prepared from 150 cm³ of 1.0mol/dm³ stock solution of the acid

Chemistry

1 answer:

Reptile [31]2 years ago

5 0

Answer:

Explanation:

250 cm^3 of 0.2 moldm-3 H2SO4 can be prepared from 150cm^3 of 1.0 moldm^-3 by dilution.

150cm^3 of the 1.0 moldm^-3 stock solution is measured out using a measuring cylinder and transferred into a 250 cm^3 standard volumetric flask and made up to mark. The resulting solution is now 250cm^3 of 0.2 moldm-3 H2SO4.

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The balanced equation for the reaction of aqueous Pb(ClO3)2 with aqueous NaI is Pb(ClO3)2(aq)+2NaI(aq)⟶PbI2(s)+2NaClO3(aq) What

ryzh [129]

Answer : The mass of $PbI_2$ precipitate produced will be, 9.681 grams.

Explanation : Given,

Molarity of NaI = 0.210 M

Volume of solution = 0.2 L

Molar mass of $PbI_2$ = 461.01 g/mole

First we have to calculate the moles of $NaI$ .

$\text{Moles of }NaI=\text{Molarity of }NaI\times \text{Volume of solution}=0.210M\times 0.2L=0.042moles$

Now we have to calculate the moles of $PbI_2$ .

The balanced chemical reaction is,

$Pb(ClO_3)_2(aq)+2NaI(aq)\rightarrow PbI_2(s)+2NaClO_3(aq)$

From the balanced reaction we conclude that

As, 2 moles of $NaI$ react to give 1 mole of $PbI_2$

So, 0.042 moles of $NaI$ react to give $\frac{0.042}{2}=0.021$ moles of $PbI_2$

Now we have to calculate the mass of $PbI_2$ .

$\text{Mass of }PbI_2=\text{Moles of }PbI_2\times \text{Molar mass of }PbI_2$

$\text{Mass of }PbI_2=(0.021mole)\times (461.01g/mole)=9.681g$

Therefore, the mass of $PbI_2$ precipitate produced will be, 9.681 grams.

6 0

3 years ago

This law brings Boyle's, Charle's, Avogadro's, and Gay-Lussac's laws together in one neat, easy to use package: PV = nRT. Using

NikAS [45]

Answer:

22.4L

Explanation:

The following data were obtained from the question:

P = 1atm

T = 273K

n = 1mole

R = 0.08206 L∙atm/mol∙K

V =?

PV = nRT

V = nRT/P

V = (1 x 0.08206 x 273)/1

V = 22.4L

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2 years ago

According to the iupac convention, alkyl substituents on a hydrocarbon chain should be listed in which order?

saveliy_v [14]

According to the iupac convention, alkyl substituents on a hydrocarbon chain should be listed in alphabetical without taking prefixes into name.

A hydrocarbon would be an organic molecule in organic chemistry that is made completely of hydrogen as well as carbon. A good example of group 14 hydrides includes hydrocarbons. In general, hydrocarbons lack color and are hydrophobic. Typically, their faint smells are compared to that of gasoline and lighter fluid.

The longest unbroken carbon chain should be found and named.
Name the groups that make up this chain but instead identify them.
Beginning at the end of the chain closest to a substituent group, fraction the chain sequentially.
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Therefore, according to the iupac convention, alkyl substituents on a hydrocarbon chain should be listed in alphabetical without taking prefixes into name.

To know more about hydrocarbon

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1 year ago

All of the following are diatomic molecules except? a)H b)Br c) CI d)S

xxTIMURxx [149]

<span>d)S is not one of them.

Here's an easy way to remember them, attached: </span>

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2 years ago

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What does electronegativity measure

Rainbow [258]

Electronegativity is a measure of an atom's ability to attract shared electrons to itself. On the periodic table, electronegativity generally increases as you move from left to right across a period and decreases as you move down a group.

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2 years ago

describe how 250 cm³ of 0.2 mol/dm³ H2SO4 could be prepared from 150 cm³ of 1.0mol/dm³ stock solution of the acid​

describe how 250 cm³ of 0.2 mol/dm³ H2SO4 could be prepared from 150 cm³ of 1.0mol/dm³ stock solution of the acid