Answer:
The answer is: 11759 Hz
Explanation:
Given: Chemical shift: δ = 211.5 ppm, Spectrometer frequency = 556 MHz = 556 × 10⁶ Hz
In NMR spectroscopy, the chemical shift (δ), expressed in ppm, of a given nucleus is given by the equation:



<u>Therefore, the signal is at 11759 Hz from the TMS.</u>
The answer to problem is [He] 2s1. Hope it helps
It’s charge was neutral due to the equal number of protons and electrons. when it becomes an ion it loses 3 electrons leaving behind only 10. the answer is 10. the equation is +13 +(-10)=+3
4p, 3d, 3p, 3s, 2p, 2s and 1s orbitals may be occupied during de-excitation.<span />
Answer:
its d, forming a hypothesis is always one of the first things you do, and d is the best answer from these 4