Answer:
Kenny is 18 years old Andrew is 10 years old Tim is 30 years old and Cameron is 5 years old
Step-by-step explanation:
Let a be Kenny's age , b be Andrew's age , c be Tim's age , d be Cameron's age
( b < a , b<c , d<b)
Kenny is 8 years older than Andrewn = > a = b + 8 (1)
Tim is 3 times as old as Andrew => c = 3 . b (2)
Cameron is 5 years younger than Andrew => d = b-5 (3)
The combined age of the four is 63 => a+b+c+d = 63 (4)
(1),(2),(3),(4) => b+8 + b + 3b + b-5 = 63 <=> 6b + 3 = 63 <=> b = 10
=> a= 10+8 =18, c = 3 . 10 = 30, d= 5
Answer:
number of possible combinations = 676000
Explanation:
We have:
26 possible letters (a to z)
10 possible digits(0 to 9)
2 letters followed by 3 digits
For letters, since repetition is allowed, therefore, each of the two letters can be any of the possible 26 alphabetical letters (a to z)
For digits, since repetition is allowed, therefore, each digit of the three can be any of the possible 10 digits (0 to 9)
Therefore:
number of combinations = letter * letter * digit * digit * digit
number of combinations = 26 * 26 * 10 * 10 * 10
number of possible combinations = 676000
Hope this helps :)
Answer:
Step-by-step explanation:
x^2 = 256 + 12^2
