The calculated pH of the solutions are given below:
- The pH of the solution after 14.0 ml of base is added to it is calculated as 1.45.
- The pH of the solution after 19.8 ml of base is added to it is calculated as 3.0
- The pH of the solution after 20.0 ml of base is added to it is calculated as 7.
<h3>What is pH?</h3>
This is the level of acidity or alkalinity of an aqueous solution. The pH of a substances tells if its an acid, base or neutral.
HBr and NaOH while in water would dissociate and they would become H+ and OH- respectively.
Mol of HBr = Mol * Vol
= 0.200 * 20mL
= 4 mmol
A. Moles of NaOH added
= 0.2 X 14
= 2.8 mmol
Moles of H+ that did not react
= 4 - 2.8
= 1.2 mmol
1.2/1000 = 0.0012 moles
Total volume = 20 + 14
= 34 mL to litres
= 0.034 L
Molarity of H+ = 0.0012 / 0.034L
= 0.035 M
-log[0.035] = 1.45
The pH of the solution is 1.45
B. NaOH added = 19.8 * 0.2 =
3.96 mmoles
The unreacted solution
= 4.0 - 3.96
= 0.04 mmol
0.04/1000 = 0.00004 moles
Total volume = 20 + 19.8
= 39.8mL
Converted to litres = 0.0398L
Molarity = 0.00004 / 0.0398L
= 0.001
-log(0.001) = 3.0
The ph Is therefore 3.0
C. Moles of NaOH added = 0.2*20mL = 4mmol
All the H+ are going to be consumed here. This would result into a neutral solution pH = 7
<u>Complete question:</u>
20.0 mL sample of 0.200 M HBr solution is titrated with 0.200 M NaOH solution. Calculate the PH of the solution after the following volumes of base have been added.
A. 14.0 mL
B. 19.8 mL
C. 20.0 mL
Read more on pH here; brainly.com/question/22390063
Electricity, like in electric cars
Based on the calculations, we have the following:
- The area of the sheet of paper is 96 square inches.
- The combined area of the triangle cutouts is equal to 36 square inches.
- The area of the parallelogram is equal to 60 square inches.
- The altitude of the parallelogram is equal to 6.51 square inches.
<u>Given the following data:</u>
- Dimension of paper = 12-inch by 8-inch.
<h3>How to calculate the paper's area.</h3>
Mathematically, the area of the paper is given by this formula:
Area = 96 square inches.
<u>For the four (4) right triangles:</u>
- Dimension 1 = 2 inches by 9 inches.
- Dimension 2 = 3 inches by 6 inches.
Therefore, the combined area of the triangle cutouts is given by:
<h3>The area of the parallelogram.</h3>
This would be determined by subtracting the area of the four (4) right triangles from the areas of the paper as follows:
P = 60 square inches.
<h3>The altitude of the
parallelogram.</h3>
Altitude = 6.51 square inches.
Read more on parallelogram here: brainly.com/question/4459854
<u>Complete Question:</u>
A parallelogram is cut out of a 12-inch by 8-inch sheet of paper. There are four right triangle remnants. Two have the dimensions 2 inches by 9 inches, and the other two have the dimensions 3 inches by 6 inches. The resulting parallelogram has a base of approximately 9.22 inches.
Answer: Input. Basic. variables
Explanation: there is no explanation
