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xz_007 [3.2K]
3 years ago
12

What is the range of the discrete finite function mapped below?

Mathematics
1 answer:
asambeis [7]3 years ago
8 0

Answer:

<em> </em><em>your</em><em> </em><em> </em><em>right</em><em> </em><em>is</em><em> </em><em>(</em><em>C</em><em>)</em><em> </em><em> </em>

<em>hope</em><em> </em><em>it's</em><em> </em><em>help</em><em> </em><em>you</em><em> </em><em>(</em><em>^</em><em>0</em><em>^</em><em>)</em><em> </em>

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I need help pls!!!!!​
svp [43]

Answer:

AP EURO DBQ RUBRIC. Updated July 2017. Name: DBQ: CONTEXTUALIZATION. Describes a broader historical context

4 0
3 years ago
Alec bakes spherical rolls of bread. Each roll is about 8cm
Fantom [35]

Answer:

Step-by-step explanation:

2143.57

6 0
3 years ago
<img src="https://tex.z-dn.net/?f=g%28x%29%20%3D%20%28x%20-%201%29%20%7B%7D%5E%7B2%7D%20%20-%203" id="TexFormula1" title="g(x) =
I am Lyosha [343]

Answer:

9.

Step-by-step explanation

g(x) = (x - 1)^2 - 3

g(1) = (1-1)^2 - 3 = -3

so g^2 (1) = (-3) ^2

= 9.

3 0
4 years ago
Construct the 90% confidence interval for the proportion of students at the college who have completed their required English 10
igomit [66]

Answer:

The confidence interval has an lower limit of \pi - z\sqrt{\frac{\pi(1-\pi)}{n}} = \pi - 1.645\sqrt{\frac{\pi(1-\pi)}{n}} and an upper limit of \pi + z\sqrt{\frac{\pi(1-\pi)}{n}} = \pi + 1.645\sqrt{\frac{\pi(1-\pi)}{n}}, in which \pi is the sample proportion and n is the size of the sample.

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of \pi, and a confidence level of 1-\alpha, we have the following confidence interval of proportions.

\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}

In which

z is the z-score that has a p-value of 1 - \frac{\alpha}{2}.

90% confidence level

So \alpha = 0.1, z is the value of Z that has a p-value of 1 - \frac{0.1}{2} = 0.95, so Z = 1.645.

The lower limit of this interval is:

\pi - z\sqrt{\frac{\pi(1-\pi)}{n}} = \pi - 1.645\sqrt{\frac{\pi(1-\pi)}{n}}

The upper limit of this interval is:

\pi + z\sqrt{\frac{\pi(1-\pi)}{n}} = \pi + 1.645\sqrt{\frac{\pi(1-\pi)}{n}}

The confidence interval has an lower limit of \pi - z\sqrt{\frac{\pi(1-\pi)}{n}} = \pi - 1.645\sqrt{\frac{\pi(1-\pi)}{n}} and an upper limit of \pi + z\sqrt{\frac{\pi(1-\pi)}{n}} = \pi + 1.645\sqrt{\frac{\pi(1-\pi)}{n}}, in which \pi is the sample proportion and n is the size of the sample.

8 0
4 years ago
A salesman for a shoe company claimed runners would run faster races if they wore the company's brand of running shoe. A track c
gregori [183]

Answer:

Correct option: (c) Paired samples t confidence interval.

Step-by-step explanation:

A paired data is collected from an experiment that is conducted twice; once before applying a treatment and second time after the treatment has been applied.

For example, scores of students before the coaching classes and after the coaching classes.

In this case a paired data is collected.

The runners were asked to run 100-yard wearing their usual shoes one day and do same thing the next day wearing the company's shoes.

The two data collected from both the days is a paired data.

To determine whether the salesman's claim that the runners would run faster races if they wore the company's brand of running shoe is correct or not a confidence interval can be constructed for the paired the data.

If the true mean difference is contained in the interval then the salesman's claim can be considered true otherwise false.

To construct this confidence interval use a paired sample t confidence interval.

Because the population standard deviations are not known.

The (1 - <em>α</em>)% confidence interval for the paired difference is:

CI=\bar X_{diff}\pm t_{\alpha/2, (n-1)} \frac{\hat \sigma_{diff}}{\sqrt{n}}

3 0
3 years ago
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