Answer: The voids between stars in our galaxy can be filled with tenuous clouds of gas and other molecules. ... That material gets "ripped away" from the galaxies by the force of gravity, and often enough it collides with other material.
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Lead-207 can change into Lead-208.
When Lead-207 is bombarded with neutrons, the atom acquires the neutron. Adding a neutron only changes the mass number of the atom. This does not involve change in the identity of the atom. So, Lead-207 can change into Lead-208 without change in its chemical properties.
Answer: Option (C) is the correct answer.
Explanation:
When yeast is added into a bottle with water and sugar then after some time yeast becomes activated. This results in the formation of a chemical change as bubbles are formed on the surface of the mixture in the bottle.
This indicates that a gas has been released due to the chemical change.
Thus, we can conclude that most likely a chemical change has occurred because a gas was produced.
Units of impulse: N • s, kg • meters per second
Explanation:
Impulse is defined in two ways:
1)
Impulse is defined as the product between the force exerted in a collision and the duration of the collision:

where
F is the force
is the time interval
Since the force is measured in Newtons (N) and the time is measured in seconds (s), the units for the impulse are
![[I] = [N][s]](https://tex.z-dn.net/?f=%5BI%5D%20%3D%20%5BN%5D%5Bs%5D)
So,
N • s
2)
Impulse is also defined as the change in momentum experienced by an object:

where the change in momentum is given by

where m is the mass and
is the change in velocity.
The mass is measured in kilograms (kg) while the change in velocity is measured in metres per second (m/s), therefore the units for impulse are
![[I]=[kg][m/s]](https://tex.z-dn.net/?f=%5BI%5D%3D%5Bkg%5D%5Bm%2Fs%5D)
so,
kg • meters per second
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Answer:
388.97 nm
Explanation:
The computation of the wavelength of this light in benzene is shown below:
As we know that
n (water) = 1.333
n (benzene) = 1.501

And, the wavelength of water is 438 nm
![\lambda (benzene) = \lambda (water) [\frac{n(water)}{n(benzene}]](https://tex.z-dn.net/?f=%5Clambda%20%28benzene%29%20%3D%20%5Clambda%20%28water%29%20%5B%5Cfrac%7Bn%28water%29%7D%7Bn%28benzene%7D%5D)
Now placing these values to the above formula
So,

= 388.97 nm
We simply applied the above formula so that we can easily determine the wavelength of this light in benzene could come