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Lunna [17]
3 years ago
5

The current through a particular circuit

Engineering
1 answer:
timofeeve [1]3 years ago
3 0

Answer:

I think a circular particular circuit element is given by it equals 5  200.8 e blah blah blah blah

Explanation:

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A commercial facility has a three-phase, 277 volt, 1200 Amp service. What is the required nominal transformer size needed for th
alekssr [168]

Answer:

The answer is "Option e".

Explanation:

Given value:

\to v_{ph}=277  \ \ \ \ \ \ \  I_{ph} =1200\\\\

vA= v_{Ph} I_{ph}  \  \ \ \to  for \ single \ phase\\\\=3v_{ph} I_{ph}  \ \ \ \ \ \to  for \ 3 - \phi  \\\\s = 3\times 277 \times 1200 \\\\

  =997.200 \ K VA\\\\= 1000 \ k VA

7 0
3 years ago
Find the total amount of heat in Q lost through a wall 10' by 18' , with R value from q. 1. Inside temperature is 70 degrees F w
marissa [1.9K]

Answer:

Just think

Explanation:

6 0
4 years ago
Read 2 more answers
Under normal conditions, gauge pressure is ______ absolute pressure.
levacccp [35]

Answer:

Option B  Lower than

Explanation:

Gauge pressure is a relative measurement based on atmospheric pressure. Gauge pressure can be positive if it is above atmospheric pressure or it can also be negative it is below.  On another hand, absolute pressure is an actual pressure in a space and its value has always to be zero or above. Basically absolute pressure is zero if it is in a perfect vacuum. So the measurement of absolute pressure is gauge pressure + atmospheric pressure.  This is the reason in normal condition the gauge pressure = absolute pressure - atmospheric pressure and therefore is lower than absolute pressure

3 0
4 years ago
A vehicle of 1 200 kg is moving at a speed of 40 km/h on an incline of 1 in 50. The total constant rolling and wind resistance i
Readme [11.4K]

Answer:11.602 KW

Explanation:

mass of vehicle\left ( m\right )=1200 kg

speed=40Km/h

Resistance=600 N

\eta =80%

Gear ratio\left ( G\right )=4:1

D_{effective}=500mm

Net force to overcome by engine is

F=Resistance + sin component of weight

F=600+mgsin\theta

Where tan\theta =[tex]\frac{1}{50}

\theta =1.1457^{\circ}

F=600+1200\times 9.81\times sin\left ( 1.1457\right )

F=600+235.38=835.38 N

power=F.v=835.38\frac{100}{9}

Engine Power=\frac{835.\frac{100}{9}}{\eta }=11.602 KW

4 0
4 years ago
In a shear cutting process, a sheet of soft cold-rolled steel has a thickness of 2 mm and a width of 1 m. The yield strength and
Ganezh [65]
Sorry I don’t know the answer I just need to answer some questions before I can get my own work done
6 0
3 years ago
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