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ale4655 [162]
3 years ago
14

if you had 100 B size sheets and you cut them into A size sheets, how many sheets of A size paper would you have

Engineering
1 answer:
castortr0y [4]3 years ago
8 0

Answer:

200

Explanation:

A size sheets (also known as letter size) are 8.5 inches by 11 inches.

B size sheets (also known as ledger size) are 11 inches by 17 inches.

One B size sheet is twice as large as a A size sheet.  So if you have 100 B size sheets and cut each one in half, you'll get 200 A size sheets.

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kolezko [41]

Answer:

i liked the vid

Explanation:

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5 0
3 years ago
A bird is flying in air. It is stretching its wings all along the sky and is flying in a certain direction Flying a bird is an e
guapka [62]

Answer:

a. Composition of Vector.

Explanation:

When a bird flies in the air, it stretches its wings into air and this movement helps it move in a certain direction. This is an example of composition of vector. Air strikes the wings in opposite direction and bird wing movement helps it move against the wind.

3 0
3 years ago
Identify the unit of the electrical parameters represented by L and C and prove that the resonant frequency (fr)=1÷2π√LC
Gre4nikov [31]

Answer:

L = Henry

C = Farad

Explanation:

The electrical parameter represented as L is the inductance whose unit is Henry(H).

The electrical parameter represented as C is the inductance whose unit is Farad

Resonance frequency occurs when the applied period force is equal to the natural frequency of the system upon which the force acts :

To obtain :

At resonance, Inductive reactance = capacitive reactance

Equate the inductive and capacitive reactance

Inductive reactance(Xl) = 2πFL

Capacitive Reactance(Xc) = 1/2πFC

Inductive reactance(Xl) = Capacitive Reactance(Xc)

2πFL = 1/2πFC

Multiplying both sides by F

F * 2πFL = F * 1/2πFC

2πF²L = 1/2πC

Isolating F²

F² = 1/2πC2πL

F² = 1/4π²LC

Take the square root of both sides to make F the subject

F = √1 / √4π²LC

F = 1 /2π√LC

Hence, the proof.

8 0
3 years ago
Argon is compressed in a polytropic process with n = 1.2 from 120 kPa and 10°C to 850 kPa in a piston–cylinder device. Determine
Ivenika [448]

Answer:

W=-109.12 kJ/kg

Q=-76.34 kJ/kg

Explanation:

The needed work W we will calculate by using the work equation for polytropic process and the heat transfer Q we will calculate by using the energy balance equation.

Before the calculations we first need to determine the final temperature T2. We will do that by using the given initial temperature T1 = 10°C, the given initial p_1 = 120 kPa and final p_2 = 800 kPa pressure and the polytropic index n = 1.2. Before the calculation we need to express the temperature in K units.  

T1 = 10°C + 273 K = 283 K  

T2 = ((p_2/p_1)^(n-1)/n)* T1

T2 = 388 K

Now we can use the heat capacity C_v, = 0.3122 kJ /kg K and the temperatures T1 and T2 to determine the change in internal energy ΔU.  

ΔU = C_v*(T2-T1)

ΔU = 32.78 kJ/kg

to determine the work we will also need the initial v1 and final v2 specific volume. The initial specific volume v1 we can determine from the ideal gas equation. For the calculation we will need the initial pressure p_1, temperature T1 and the specific gas constant R = 0.2081 kJ /kg K.  

v1=R*T1/p_1

v1=0.4908 m^3/kg

For the final specific volume we need to replace the initial temperature and pressure with the final.  

v2=R*T2/p_2

v2=0.1009 m^3/kg

The work W is then:  

W=p_2*v2-p_1*v1/n-1

W=-109.12 kJ/kg

The heat transfer Q we can calculate form the energy balance equation. For the calculation we will need the calculated work W and the change in internal energy ΔU.  

Q=W+ΔU

Q=-76.34 kJ/kg

7 0
4 years ago
Helium gas is compressed from 90 kPa and 30oC to 450 kPa in a reversible, adiabatic process. Determine the final temperature and
ra1l [238]

Answer:

T2 ( final temperature ) = 576.9 K

a) 853.4 kJ/kg

b) 1422.3 kJ / kg

Explanation:

given data :

pressure ( P1 ) = 90 kPa

Temperature ( T1 ) = 30°c + 273 = 303 k

P2 = 450 kPa

Determine final temperature for an Isentropic  process

T2 = T1 (\frac{p2}{p1} )^{(k-1)/k}  ----------- ( 1 )

T2 = 303 ( \frac{450}{90})^{(1.667- 1)/1.667} =  576.9K

Work done in a piston-cylinder device can be calculated using this formula

w_{in} = c_{v} ( T2 - T1 )    ------- ( 2 )

where : cv = 3.1156 kJ/kg.k  for helium gas

             T2 = 576.9K ,    T1 = 303 K

substitute given values Back to equation 2

w_{in}  = 853.4 kJ/kg

work done in a steady flow compressor can be calculated using this

w_{in} = c_{p} ( T2 - T1 )

where : cp ( constant pressure of helium gas )  = 5.1926 kJ/kg.K

             T2 = 576.9 k , T1 = 303 K

substitute values back to equation 3

w_{in} = 1422.3 kJ / kg

4 0
3 years ago
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