To solve this problem it is necessary to apply the concepts related to the Period of a body and the relationship between angular velocity and linear velocity.
The angular velocity as a function of the period is described as
Where,
Angular velocity
T = Period
At the same time the relationship between Angular velocity and linear velocity is described by the equation.
Where,
r = Radius
Our values are given as,
We also know that the radius of the earth (r) is approximately
Usando la ecuación de la velocidad angular entonces tenemos que
Then the linear velocity would be,
x
The speed would Earth's inhabitants who live at the equator go flying off Earth's surface is 463.96
When Angel hits a ball with the ball. As the action is a ball as it is hitted. The reaction force is the force exerted on another ball.
Newton’s third law of motion describes the two forces, action and reaction forces. This states that for every action force, there is an equal and opposite reaction force.
As Angel hits a ball with another ball, the action is the ball as it is hit. The ball exerts a force on the ball. This is the action force. The ball exerts an equal and opposite force on the bat, which is known as the reaction force.
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Answer:
19.9 N/m
Explanation:
From the question,
Applying Hook's law
F = Ke.................. Equation 1
Where F = Force on the spring, k = spring constant, e = extension
But the force on the spring is the weight of the mass
Therefore,
mg = ke.................. Equation 2
Where m = mass. g = acceleration due to gravity
make e the subject of the equation
e = mg/e................ Equation 3
Given: m = 455 g = 0.455 kg, e = 22.4 cm = 0.224 m,
Constant: g = 9.8 m/s²
Substitute these values into equation 3
e = (0.455×9.8)/0.224
e = 19.9 N/m
It is calculated that a)The angular velocity of the wheel is 272.13 rad/s,
b)On the edge of the grinding wheel, the linear speed is 47.62 m/s,
and c) On the edge of the grinding wheel, the acceleration is 12958.08 m/s².
Calculation of angular velocity, linear speed & acceleration:
Provided that,
the diameter of the wheel = 0.35 m
So, the radius, r = 0.35/2 = 0.175 m
As 1 revolution = 2π rad
(a)the angular velocity, ω = 2600 rpm = 
rad/s
⇒ω = 272.13 rad/s
So, the angular velocity is 272.13 rad/s.
(b)The linear speed, v = r * ω
⇒v = 0.175 * 272.13
⇒v= 47.62 m/s
(c)The angular acceleration, 
⇒
= 12958.08 m/s²
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Answer:
25,300,000,000,000 miles away
