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Advocard [28]
3 years ago
9

Steve is planning his annual Spring Break road trip. He pulls out his map and draws out his route to visit the five locations th

at he has planned for this year. They go in a counterclockwise loop and he ends up at home, where he started, just in time to start classes again. Whenever he is on the road he travels a constant 60 miles/hour. When Steve adds up the total distance traveled, as measured by his odometer, and divides it by the time that his trip took, he has measured what quantity?
a. His average velocity.
b. His average speed.
c. His instantaneous velocity.
d. His instantaneous speed.
Physics
1 answer:
Aleksandr [31]3 years ago
8 0

Answer:

His average speed.

Explanation:

Average speed = Total distance travelled / total time .

In the given case odometer measures total distance travelled . Dividing it by time will give average speed .

Average velocity can not be the answer as it is measured by dividing displacement by time . Displacement here is zero because initial and final point are same . Instantaneous velocity is given by the speedometer . It keeps on changing all the time . It is actually speed at a particular point of time . It can not be average velocity or speed .

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An airplane maintains a speed of 627 km/h relative to the air it is flying through as it makes a trip to a city 787 km away to t
amid [387]

Answer:1.33 hr

Explanation:

Given

Speed of airplane relative to air=627 km/h

Distance traveled =787 km

Speed of wind=38.4 km/h

Wind is blowing in opposite direction therefore net speed is

v_{net}=627-38.4=588.6 km/h

thus time taken is

t=\frac{distance}{speed}

t=\frac{787}{588.6}=1.33 hr

4 0
4 years ago
Q7) A box sliding with a velocity of 5 m/s accelerates at 2 m/s^2. How
grigory [225]

Answer:

The box displacement after 6 seconds is 66 meters.

Explanation:

Let suppose that velocity given in statement represents the initial velocity of the box and, likewise, the box accelerates at constant rate. Then, the displacement of the object (\Delta s), in meters, can be determined by the following expression:

\Delta s = v_{o}\cdot t+\frac{1}{2}\cdot a\cdot t^{2} (1)

Where:

v_{o} - Initial velocity, in meters per second.

t - Time, in seconds.

a - Acceleration, in meters per square second.

If we know that v_{o} = 5\,\frac{m}{s}, t = 6\,s and a = 2\,\frac{m}{s^{2}}, then the box displacement after 6 seconds is:

\Delta s = 66\,m

The box displacement after 6 seconds is 66 meters.

5 0
3 years ago
Why are microwaves beneficial to use for transmitting information
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5 0
4 years ago
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Ainat [17]
To be honest, the picture is so far above that I can't see it at all.
But reading the information in the question's statement, I'd say
the blank should be filled in so that it says:

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8 0
4 years ago
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