Answer:
a)
b) is the limiting reagent
c) Moles of produced = 2.45 mol
b) Moles of left = 1.75 -1.22 = 0.53
Explanation:
a) Balanced reaction:
b)
No. of mole of
No. of mole of
As, it is clear from the reaction that,
1 mol of requires 3 moles of
1.75 mol of require = 1.75 × 3 = 5.25 mol of
As, only 3.68 mol of is present, so is the limiting reagent.
c)
3 moles of form 2 moles of
3.68 moles of will form =
d)
is present in excess.
3 moles of requires 1 mol of
3.68 moles of will require =
left = 1.75 -1.22 = 0.53 mol
Answer:
A solution
Explanation:
The solute is the substance being dissolved by another substance
There are three: Hydrogen, Nitrogen, and Oxygen.
Hey there!
C₇H₉+ HNO₃ → C₇H₆(NO₂)₃+ H₂O
Our elements: C, H, N, and O.
Balance H.
Ten on the left, eight on the right. Add a coefficient of 2 in front of H₂O.
C₇H₉+ HNO₃ → C₇H₆(NO₂)₃+ 2H₂O
Balance N.
One on the left, three on the right. Add a coefficient of 3 in front of HNO₃.
C₇H₉+ 3HNO₃ → C₇H₆(NO₂)₃+ 2H₂O
This unbalanced H, let's increase the coefficient in front of H₂O from 2 to 3 to rebalance.
C₇H₉+ 3HNO₃ → C₇H₆(NO₂)₃+ 3H₂O
Balance O.
Nine on the left, nine on the right. Already balanced.
Balance C.
Seven on the left, seven on the right. Already balanced.
Our final balanced equation:
C₇H₉+ 3HNO₃ → C₇H₆(NO₂)₃+ 3H₂O
Hope this helps!
An atom of fluorine would possess 7 valence electrons as it is found in group 7 of the periodic table.
The group number in this case corresponds to the number of valence electrons present.
So, for instance, because Chlorine is also found in group 7, it would also have 7 valence electrons.