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3 years ago

Distringuish between zeotropic and azeotropic mixtures

2 answers:

7 0

Namely, azeotropic mixtures have dew and bubble curves that intersect, but zeotropic mixtures do not. In other words, zeotropic mixtures have no azeotropic points. An azeotropic mixture that is near its azeotropic point has negligible zeotropic behavior and is near-azeotropic rather than zeotropic.

myrzilka [38]3 years ago

3 0

Answer:

The terms azeotropic and zeotropic are opposite to each other. The key difference between azeotropic and zeotropic mixture is that the dew point and bubble point of an azeotropic mixture intersect, whereas the dew point and bubble point of a zeotropic mixture are distinguishable.

Explanation:

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How long does it take to electroplate 0.5 mm of gold on an object with a surface area of 31 cm^^ from an Au3+(aq) solution with

konstantin123 [22]

Answer:

It will take 5492 seconds to electroplate 0.5 mm of gold on an object .

Explanation:

Mass of gold = m

Volume of gold = v

Surface area on which gold is plated = $a=31 cm^2$

Thickness of the gold plating = h = 0.5 mm = 0.05 cm

1 mm = 0.1 cm

$V=a\times h=31 cm^2\times 0.05 cm=1.55 cm^3$

Density of the gold = $d=19.3 g/cm^3$

$m=d\times v=19.3 g/cm^3\times 1.55 cm^3=29.915g$

Moles of gold = $\frac{29.915 g}{197 g/mol}=0.152 mol$

$Au^{3+}+3e^-\rightarrow Au$

According to reaction, 1 mole of gold required 3 moles of electrons,then 0.152 moles of gold will require :

$\frac{3}{1}\times 0.152 mol=0.456 mol$ of electrons

Number of electrons = N = $0.456\times \times 6.022\times 10^{23}$

Charge on single electron = $q=1.6\times 10^{-19} C$

Total charge required = Q

$Q=N\times q$

Amount of current passes = I = 8 Ampere

Duration of time = T

$I=\frac{Q}{T}$

$T=\frac{N\times q}{I}$

$=\frac{0.456\times \times 6.022\times 10^{23}\times 1.6\times 10^{-19} C}{8 A}=5492 s$

It will take 5492 seconds to electroplate 0.5 mm of gold on an object .

7 0

2 years ago

Convert 45 kL to mL (must show work)

svp [43]

Answer:

1 kiloliter = 1,000,000 milliliters

45 × 1,000,000

45 KL = 45,000,000 ML

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2 years ago

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Vanyuwa [196]

Answer:

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Explanation:

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3 years ago

Which of the following is true about homogeous mixtures

sergey [27]

Was there supposed to be a picture?

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2 years ago

Distringuish between zeotropic and azeotropic mixtures​

Distringuish between zeotropic and azeotropic mixtures