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valentinak56 [21]

2 years ago

5

in a store parking lot, the ratio of blue cars to silver cars is 2 : 3. there are 24 blue cars how many silver cars are in the l

ot ?

1 answer:

wolverine [178]2 years ago

8 0

Answer: 36

Step-by-step explanation:

There is 50% more silver cars then blue cars

Take 24 x 1.5 (50% more) and you get 36

-Gage Millar, Algebra 2 tutoe

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Name the property<br> cx1=c<br><br> 83+(52+17)=(83+52)+17<br> 22+b+18=b+22+18

jek_recluse [69]

Answer:

distributive property :)

6 0

2 years ago

Michelle is rolling two six-sided dice, numbered one through six. What is the probability that the sum of her rolls is 8?

Verdich [7]

The probability that the sum of Michelle's rolls is 4 is 0.083
∴ P(A)=0.083
Step-by-step explanation:
Given that Michelle is rolling two six-sided dice, numbered one through six.
To find the probability that the sum of her rolls is 4:

∴ n(s)=36
Let P(A) be the probability that the sum of her rolls is 4
Then the possible rolls with sums of 4 can be written as

n(A)=3
The probability that the sum of her rolls is 4 is given by

=0.083
∴ P(A)=0.083
∴ the probability that the sum of Michelle's rolls is 4 is 0.083

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3 0

2 years ago

The track club runs the 50-yard dash. How many inches do they run?

kiruha [24]

Answer:

1800in

Step-by-step explanation:

3ft=1yd

3x50=150ft

12in=1ft

12x150=1800in

8 0

3 years ago

Read 2 more answers

G(t)= t-3 <br> h(x)= 3t-2 <br> find (g-h)(t)

Marina86 [1]

Answer:

g(t) - h(t) = -2t - 1

Step-by-step explanation:

g(t) - h(t) = t-3-3t+2

= -2t -1

6 0

3 years ago

Coach Evans recorded the height, in inches of each player on his team. The results are shown.

marysya [2.9K]

Answer:

3

Step-by-step explanation:

Given:

Team heights (inches):

61, 57, 63, 62, 60, 64, 60, 62, 63

To find: IQRs (interquartile ranges) of the heights for the team

Solution:

A quartile divides the number of terms in the data into four more or less equal parts that is quarters.

For a set of data, a number for which 25% of the data is less than that number is known as the first quartile $(Q_1)$

For a set of data, a number for which 75% of the data is less than that number is known as the third quartile $(Q_3)$

Terms in arranged in ascending order:

$57,60,60,61,62,62,63,63,64$

Number of terms = 9

As number of terms is odd, exclude the middle term that is 62.

$Q_1$ is median of terms $57,60,60,61$

Number of terms (n) = 4

Median = $\frac{(\frac{n}{2})^{th} +(\frac{n}{2}+1)^{th} }{2} =\frac{2^{nd}+3^{rd}}{2} =\frac{60+60}{2}=\frac{120}{2}=60$

So, $Q_1=60$

So, 25% of the heights of a team is less than 60 inches

$Q_3$ is the median of terms $62,63,63,64$

Median = $\frac{(\frac{n}{2})^{th} +(\frac{n}{2}+1)^{th} }{2} =\frac{2^{nd}+3^{rd}}{2} =\frac{63+63}{2}=\frac{126}{2}=63$

So, $Q_3=63$

So, 75% of the heights of a team is less than 63 inches

Interquartile range = $Q_3-Q_1=63-60=3$

The interquartile range is a measure of variability on dividing a data set into quartiles.

The interquartile range is the range of the middle 50% of the terms in the data.

So, 3 is the range of the middle 50% of the heights of the students.

4 0

2 years ago