Hi there!
Recall Newton's Second Law:
∑F = Net force (N)
m = mass (kg)
a = acceleration (m/s²)
We are already given the mass and acceleration, so we can plug these values into the equation:
∑F = 1600 · 4.5 = 7200 N
SOMEONE PLS HELP ME I NEED HELP THIS IS DUE TODAY
1 answer:
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Answer:
Explanation:
From the question we are told that:
Electric Field strength
Potential difference is
Generally the equation for distance is mathematically given by
Explanation:
It is given that,
Distance, r = 3.5 m
Electric field due to an infinite wall of charges, E = 125 N/C
We need to find the electric field 1.5 meters from the wall, r' = 1.5 m. Let it is equal to E'. For an infinite wall of charge the electric field is given by :
It is clear that the electric field is inversely proportional to the distance. So,
E' = 291.67 N/C
So, the magnitude of the electric field 1.5 meters from the wall is 291.67 N/C. Hence, this is the required solution.