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Oxana [17]
3 years ago
5

two balls are dropped from rest and allowed to fall for 1 s and the other for 3 s, compare the distances they have fallen​

Physics
1 answer:
statuscvo [17]3 years ago
7 0
Answer:
distance traveled by 3 second ball ≈ 45m
distance traveled by 1 second ball ≈ 5m

Explanation:

Since the 2 balls started at rest, their v initial = 0, and since no other force is acting on them except for the gravitational force, they accelerate downwards at 10m/s2.

To calculate the distance traveled by both balls, we apply the second formula of UARM motion:

• Δx = 1/2(a)(t^2) + (v0)(t)

Applying both 1s and 3s in this formula will yield you 5m and 45m respectively.


Hope this helps, brainliest would be appreciated :)
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