First one is 5/3
Second one is: 5
Third one is: 15
There are nine possible combinations as follows: bb, bc, bt, cb, cc, ct, tb, tc, tt, each having a probability of 1/9. The four combinations with a cab exactly one time are: bc, cb, ct, tc. Therefore the probability that she'll use a cab exactly one time is: 4/9.
Answer:
2x2x2x2x2x2x2=8/3=1 2/3
8x8x8=512
1/6x1/6x1/6= 1/216
5/8x5/8=1 2/8
Step-by-step explanation:
i hope this helps
have a nice day/night
mark brainliest, please :)
