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alexandr402 [8]
3 years ago
14

Part 1 state the domain and range of the given relation.

Mathematics
1 answer:
hram777 [196]3 years ago
5 0
A relation is any set of ordered pairs, which can be thought of as (input, output).

A function is a relation in which NO two ordered pairs have the same first component and different second components.

The set of first components (x-coordinates) in the ordered pairs is the DOMAIN of the relation.

The set of second components (y-coordinates) is the RANGE of the relation.

Part 1:
Domain: {-1, 1, 3, 6}
Range: {2, 2, 2, 2}

Part 2:
To determine whether the given relation represents a function, look at the given relation and ask yourself, “Does every first element (or input) correspond with EXACTLY ONE second element (or output)?”

Remember that a function can only take on 1 output for each input.

It helps to plot the points on the graph and perform the Vertical Line Test (VLT):

The Vertical Line Test allows us to know whether or not a graph is actually a function. If a vertical line intersects the graph in all places at exactly one point, then the relation is a function.

As you can see in the attached screenshot, every vertical line drawn only has 1 point in it. This means that each x-value corresponds to exactly one y-value. The given relation passed the VLT. Therefore, the relation is a function.


Please mark my answers as the Brainliest if you find my explanation helpful :)

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4 years ago
Solve 5x^2 - 7x + 2 = 0 by completing the square.
Reika [66]

Answer:  The correct option is (c) \dfrac{49}{100}.

Step-by-step explanation:  We are given to solve the following quadratic equation by the method of completing the square:

5x^2-7x+2=0~~~~~~~~~~~~~~~~~~~(i)

Also, we are to find the constant added on both sides to form the perfect square trinomial.

We have from equation (i) that

5x^2-7x+2=0\\\\\Rightarrow x^2-\dfrac{7}{5}x+\dfrac{2}{5}=0\\\\\\\Rightarrow x^2-2\times x\times \dfrac{7}{10}+\left(\dfrac{7}{10}\right)^2+\dfrac{2}{5}=\left(\dfrac{7}{10}\right)^2\\\\\\\Rightarrow \left(x-\dfrac{7}{10}\right)^2=\dfrac{49}{100}-\dfrac{2}{5}\\\\\\\Rightarrow  \left(x-\dfrac{7}{10}\right)^2=\dfrac{49-40}{100}\\\\\\\Rightarrow  \left(x-\dfrac{7}{10}\right)^2=\dfrac{9}{100}\\\\\\\Rightarrow x-\dfrac{7}{10}=\pm\dfrac{3}{10}\\\\\\\Rightarrow x=\pm\dfrac{3}{10}+\dfrac{7}{10}.

So,

x=\dfrac{3}{10}+\dfrac{7}{10},~~~~~~~~x=-\dfrac{3}{10}+\dfrac{7}{10}\\\\\\\Rightarrow x=\dfrac{10}{10},~~~~~~~~\Rightarrow x=\dfrac{-3+7}{10}\\\\\\\Rightarrow x=1,~-\dfrac{2}{5}.

Thus, the required solution is x=1,~-\dfrac{2}{5}. and the value of the constant added is \dfrac{49}{100}.

Option (c) is correct.

3 0
3 years ago
What is an equation of the line in slope intercept form m=3 and the y-intercept is (0 4)
wlad13 [49]
Y = mx + b  (m = 3) y-intercept (0,4)

y = 3x + 4

hope this helps, God bless!
8 0
4 years ago
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BlackZzzverrR [31]
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4*3 is 12 but 4 is not a multiple of 6 

6 0
4 years ago
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∜64= 4ˣ, what is the value of x?
svlad2 [7]

Answer:

x = (2 i π n)/log(4) + log(2 sqrt(2))/log(4) for n element Z

Step-by-step explanation:

Solve for x:

2 sqrt(2) = 4^x

Hint: | Reverse the equality in 2 sqrt(2) = 4^x in order to isolate x to the left hand side.

2 sqrt(2) = 4^x is equivalent to 4^x = 2 sqrt(2):

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Hint: | Eliminate the exponential from the left hand side.

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Answer:x = (2 i π n)/log(4) + log(2 sqrt(2))/log(4) for n element Z

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