3 years ago

Which situation results in a final value of zero?

Mathematics

1 answer:

amid [387]3 years ago

3 0

B and D because 3-3 =0 and 5-5= 0.

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For what value of k does the equation 4+3x=(k+2)x+8

Elena L [17]

4+3x = (k+2)x + 8
4+2+3x = (k+2)x + 8 - 2
6+3x = (k+2)x + 6
then 3x = k+2
so k = 3X-2

6 0

4 years ago

using the formula c squared equals a squared plus b squared what is the length of side C, if B equals 20and A equals 15

Dennis_Churaev [7]

C^2 = A^2 + B^2
C^2 = 15^2 + 20^2
C^2 = 225 + 400
C^2 = 625
C = √(625)
C = 25

5 0

3 years ago

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Suppose astronomers built a 50-meter telescope. how much greater would its light-collecting area be than that of the 10-meter ke

drek231 [11]

Answer: Its light-collecting area would be 25 times greater than that of the 10-meter keck telescope.

Step-by-step explanation:

1. To solve this problem you must apply the formula for calculate the area of a circle, which is shown below:

$A=r^{2}\pi$

Where r is the radius of the circle.

2. The diameter of a circle is:

$D=\frac{r}{2}$

Where r is the radius of the circle.

3. Therefore, keeping this on mind, you have that the light-collecting area of a 50-meter keck telescope is:

$A_1=(\frac{50m}{2})^{2}\pi=1963,49m^{2}$

4. And the light-collecting area of a 10-meter keck telescope is:

$A_2=(\frac{10m}{2})^{2}\pi=78.53m^{2}$

5. Divide $A_1$ by $A_2$ , then:

$\frac{1963.49m^{2}}{78.53m^{2}}=25$

6. Therefore, its light-collecting area would be 25 times greater than that of the 10-meter keck telescope.

4 0

4 years ago

Find the value of (x+5y)' step by step

larisa86 [58]

Answer:

x²+10xy+25y²

Step-by-step explanation:

(x+5y)²=(x+5y)(x+5y)=x×x+5y×x+x×5y+5y×5y=x²+5xy+5xy+25y²=x²+10xy+25y²

But it can be much easier

(a+b)²=a²+2ab+b²

7 0

3 years ago

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A number divided by 43 as a quotient of 3 with 28 as a remainder

Darina [25.2K]

Answer:

x ÷ 43 = 3...28

Step-by-step explanation:

None

6 0

3 years ago

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