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lianna [129]
3 years ago
12

How many electrons does the oxygen atom need to become stable?

Chemistry
2 answers:
djverab [1.8K]3 years ago
8 0
Your answer would be 2 electrons
NemiM [27]3 years ago
4 0

Answer:

2 electrons

Explanation:

Oxygen has 6 valence electrons and to be stable it needs 8. That means it needs 2 more electrons to have a full octet.

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An atom has the following electron configuration 1s2 2s2 2p6 3s2 3p4 . How many valence electrons does this Atom have
yawa3891 [41]

Answer:

6

Explanation:

This atom is sulfur (if the electrons are equal to the protons/not an ion). You can tell the number of valence electrons by looking at the individual shell. The first shell (1s) can only hold 2 electrons. The second shell (2s and 2p) can hold 8 electrons. The third shell (3s and 3p), which is the valence shell, only has 6 out of its possible 8 electrons, so this atom has 6 valence electrons.

6 0
3 years ago
Which of the following is a property of matter?
lana66690 [7]

Explanation:

Matter also exhibits physical properties. Physical properties are used to observe and describe matter. Physical properties can be observed or measured without changing the composition of matter. These are properties such as mass, weight, volume, and density.

5 0
3 years ago
What object has a mass of 10 grams and a volume of 2 mL
Elena-2011 [213]

Answer:

Destiny = 5 g/ml

Explanation:

The formula for density is d=

Knowing this, divide your mass by volume:

10 g / 2 ml = 5 g/ml

Final answer:

Destiny = 5 g/ml

3 0
3 years ago
The partial pressure of N2 in the air is 593 mm Hg at 1 atm. What is the partial pressure of N2 in a bubble of air a scuba diver
Evgen [1.6K]

Answer: Partial pressure of N_{2} at a depth of 132 ft below sea level is 2964 mm Hg.

Explanation:

It is known that 1 atm = 760 mm Hg.

Also,   P_{N_{2}} = x_{N_{2}}P

where,    P_{N_{2}} = partial pressure of N_{2}

                 P = atmospheric pressure

            x_{N_{2}} = mole fraction of N_{2}

Putting the given values into the above formula as follows.

      P_{N_{2}} = x_{N_{2}}P

    593 mm Hg = x_{N_{2}} \times 760 mm Hg

       x_{N_{2}} = 0.780

Now, at a depth of 132 ft below the surface of the water where pressure is 5.0 atm. So, partial pressure of N_{2} is as follows.

         P_{N_{2}} = x_{N_{2}}P

                  = 0.78 \times 5 atm \times \frac{760 mm Hg}{1 atm}

                  = 2964 mm Hg

Therefore, we can conclude that partial pressure of N_{2} at a depth of 132 ft below sea level is 2964 mm Hg.

8 0
3 years ago
***BRAINLIEST ASNWERRR***<br>How many grams are in 34.2 moles of Lithium (Li)?​
Step2247 [10]

Mass of Li = 237.38 g

<h3>Further explanation</h3>

The mole itself is the number of particles contained in a substance amounting to 6.02.10²³  

\large {\boxed {\boxed {\bold {mol = \frac {mass} {molar \: mass}}}}

<h3>Known</h3>

Moles of Li = 34.2

Molar mass(MW) of Li = 6.941 g/mol

then mass of Lithium (Li) :

\tt mol=\dfrac{mass}{MW}\\\\mass=mol\times MW\\\\mass=34.2\times 6,941~g/mol\\\\mass=\boxed{\bold{237.38~g}}

3 0
4 years ago
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