Ask question

Ask question

All categories

2 years ago

9

A material has a density of 8.9g/cm3. You have six cubic centimeters of the substance. What is the materials mass in grams

1 answer:

dexar [7]2 years ago

3 0

<span>We know that density is equal to mass divide by volume of the material D=M/V. So then, in our case the material has a density of 8.9 gr/cm3 and the volume is 6 cm3. The mass will be M=D*V => 8.9 * 6 = 53.4 grams of substance.</span>

You might be interested in

(a) How much negative charge is on each oxygen of the carbonate ion?

Eva8 [605]

The chemical formula of a carbonate ion is CO3^2-. It is an AX3 system which means it take the trigonal planar shape. There would be two single bonds of C-O and one double bond C-O in order for C to agree with the octet rule. Two minus charges are equally distributed to the three oxygen atoms so that each oxygen of the carbonate ion would have a charge of negative 2/3.

6 0

2 years ago

A 1.00 cm2 blackbody surface emits 201 watts of radiant power. What is the temperature of the surface? Give to the nearest whole

erastovalidia [21]

Explanation:

Formula for black body radiation is as follows.

$\frac{P}{A} = \sigma \times T^{4} J/m^{2}s$

where, P = power emitted

A = surface area of black body

$\sigma$ = Stephen's constant = $5.6703 \times 10^{-8} watt/m^{2}.K^{-4}$

As area is given as 1.0 $cm^{2}$ . Converting it into meters as follows.

$1.00 cm^{2} \times \frac{(10^{-2})^{2} m^{2}}{1 cm^{2}}$ (as 1 m = 100 cm)

= $1 \times 10^{-4} m^{2}$

It is given that P = 201 watts. Hence,

$\frac{201 watts}{1 \times 10^{-4} m^{2}}$ = $5.6703 \times 10^{-8} watt/m^{2}.K^{-4} \times T^{4}$

$T^{4}$ = $35.45 \times 10^{12}$

T = $(35.45 \times 10^{12})^{1/4}$

= 8862.5 K

Thus, we can conclude that the temperature of the surface is 8862.5 K.

7 0

2 years ago

Which of these belongs in the outermost shell (energy level) of an atom?

hjlf

Answer:

C)Electrons

Explanation:

Hope this helped!!!

6 0

2 years ago

In 1928, 47.5 g of a new element was isolated from 660 kg of the ore molybdenite. the percent by mass of this element in the ore

vitfil [10]

To take the percent by mass of this element, we use the formula:

% mass = (mass of element / mass of ore) * 100%

% mass = (47.5 g / (660 kg * 1000 g / kg)) * 100*

<span>% mass = 7.20 x 10^-3 %</span>

8 0

3 years ago

Read 2 more answers

Help now im not trying to fail

Alekssandra [29.7K]

Answer:

i cant see the whats in the picture

5 0

2 years ago

Read 2 more answers