A material has a density of 8.9g/cm3. You have six cubic centimeters of the substance. What is the materials mass in grams

1 answer:

3 0

<span>We know that density is equal to mass divide by volume of the material D=M/V. So then, in our case the material has a density of 8.9 gr/cm3 and the volume is 6 cm3. The mass will be M=D*V => 8.9 * 6 = 53.4 grams of substance.</span>

You might be interested in

Question 19 of 26

Alona [7]

Answer:

3Mg(NO3)2(aq)+2Na3PO4(aq)⇒Mg3(PO4)2(s)+6NaNO3(aq)

Explanation:

4 0

3 years ago

Costco installs automobile tires on a first-come first-serve basis. the total time a customer needs to wait for the installation

den301095 [7]

There you go that’s the answer

3 0

3 years ago

What makes the peer-review process important to our society? Explain your answer.

Lelechka [254]

Answer:

by doing stool hahhahahhaha

3 0

3 years ago

Read 2 more answers

How should students prepare to use chemicals in the lab?.

Serggg [28]

Answer:

Become familiar with the chemicals to be used, including exposure or spill hazards.

Locate the spill kits and understand how they are used.

Explanation:

Hope this helped! :)

6 0

2 years ago

Suppose you wanted to make a buffer of exactly ph 7.00 using kh2po4 and na2hpo4. if the final solution was 0.10 m in kh2po4, wha

OleMash [197]

Answer:- 0.138 M

Solution:- The buffer pH is calculated using Handerson equation:

$pH=pKa+log(\frac{base}{acid})$

$KH_2PO_4$ acts as a weak acid and $Na_2HPO_4$ as a base which is pretty conjugate base of the weak acid we have.

The acid hase two protons(hydrogen) where as the base has only one proton. So, we could write the equation as:

$H_2PO_4^-\rightleftharpoons H^++HPO_4^-^2$

Phosphoric acid gives protons in three steps. So, the above equation is the second step as the acid has only two protons and the base has one proton.

So, we will use the second pKa value. The acid concentration is given as 0.10 M and we are asked to calculate the concentration of the base to make a buffer of exactly pH 7.00.

Let's plug in the values in the equation:

$7.00=6.86+log(\frac{base}{0.10})$