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Rainbow [258]
3 years ago
11

Which region in the IR spectrum could be used to distinguish between butanoic acid and 2-butanone?

Chemistry
1 answer:
Tems11 [23]3 years ago
4 0

Answer:2500-3300cm^{-1}

Explanation:We can distinguish between 2-butanone and butanoic acid by analyzing the spectra .                                          

The structure of the two compounds are slightly different as butanoic acid has an OH group whereas for 2-butanone there is no OH group present.

Please refer the attachments for structure of compounds.

Both the compounds will show carbonyl stretching frequency at around 1700-1750cm^{-1}[/tex] due to the presence of carbonyl group in both the compounds.

A broad intense peak at around 3000cm^{-1} will be observed only for butanoic acid due to the presence of OH group and 2-butanone would not show any broad intense peak at around 3000cm^{-1}.

So by analyzing the IR spectra and identifying the intense broad peak of OH we can easily distinguish between butanoic acid and 2-butanone.

Due to hydrogen bonding in between two carboxylic acid molecules ,peak broadening for OH group in butanoic acid takes place.

Generally the ketones show IR stretching in around 1700-1730cm^{-1}[/tex] due to the presence of carbonyl group.

Generally carboxylic acids show IR stretching  for carbonyl group at around 1700-1760cm^{-1}[/tex] and a broad intense peak for OH at around 2500-3000cm^{-1}[/tex].

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Convert 614 Cal to J. Only include the numerical value in your answer. Respond with the correct number of significant figures in
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Answer:

Explanation:

Given parameters:

Number of given calories = 614 cal

Note that  1cal = 4.18J

Now to convert the given calories to joule, we use the relationship below:

         Since 1Cal gives 4.18Joule of energy

                614Cal will produce 4.18 x 614;

                   2566.52J of energy.

This written as 2.57 x 10³J because it has three significant numbers of 2, 5 and 7.

In writing an operation that involves deducing the significant numbers, we simply express our answer to that shows the lowest number of significant numbers. Our problem has 3 significant numbers each and the answer is given in that regard.

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Water and minerals move up the xylem because of a vacuum created by _____.
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The right answer is B) evaporation

Explanation:

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What is the transfer of electrons in Al + Cl = AlCl3
otez555 [7]

Answer:

3 e⁻ transfer has occurred.

Explanation

This is a redox reaction.

  • Oxidation (loss of electrons or increase in the oxidation state of entity)
  • Reduction (gain of electrons or decrease in the oxidation state of the entity)
  • An element undergoes oxidation or reduction in order to achieve a stable configuration. It can be an octet or duplet configuration. An octet configuration is that of outer shell configuration of noble gas.
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A combination of both the reactions( Half-reactions) leads to a redox reaction.

Let us look at initial configurations of Al and Cl

[Al]= 1s² 2s² 2p⁶ 3s² 3p¹

[Cl]= 1s² 2s² 2p⁶ 3s² 3p⁵

Hence, Al can lose 3 electrons to achieve octet config.

and, Cl can gain 1e to achieve nearest noble gas config. [Ar]

This reaction can be rewritten, by clearly mentioning the oxidation states of all the entities involved.

Al⁰ + Cl⁰ → (Al⁺³)(Cl⁻)₃

Here, Aluminum is undergoing an oxidation(i.e loss of electrons) from: 0→(+3)

Chlorine undergoes a reduction half reaction (i.e gain of electrons) from: 0→(-1). There are 3 such chlorine atoms, hence 3 e⁻ transfer has occurred.

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3 years ago
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