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Rainbow [258]
3 years ago
11

Which region in the IR spectrum could be used to distinguish between butanoic acid and 2-butanone?

Chemistry
1 answer:
Tems11 [23]3 years ago
4 0

Answer:2500-3300cm^{-1}

Explanation:We can distinguish between 2-butanone and butanoic acid by analyzing the spectra .                                          

The structure of the two compounds are slightly different as butanoic acid has an OH group whereas for 2-butanone there is no OH group present.

Please refer the attachments for structure of compounds.

Both the compounds will show carbonyl stretching frequency at around 1700-1750cm^{-1}[/tex] due to the presence of carbonyl group in both the compounds.

A broad intense peak at around 3000cm^{-1} will be observed only for butanoic acid due to the presence of OH group and 2-butanone would not show any broad intense peak at around 3000cm^{-1}.

So by analyzing the IR spectra and identifying the intense broad peak of OH we can easily distinguish between butanoic acid and 2-butanone.

Due to hydrogen bonding in between two carboxylic acid molecules ,peak broadening for OH group in butanoic acid takes place.

Generally the ketones show IR stretching in around 1700-1730cm^{-1}[/tex] due to the presence of carbonyl group.

Generally carboxylic acids show IR stretching  for carbonyl group at around 1700-1760cm^{-1}[/tex] and a broad intense peak for OH at around 2500-3000cm^{-1}[/tex].

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Answer:

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<u>Explanation:</u>

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X^{n+}+ne^-\rightarrow X

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8 0
3 years ago
Select the correct hybridization for the central atom based on the electron geometry cocl2 (carbon is the central atom).
Rainbow [258]
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Sp, Sp² and Sp³ can be calculated very simply by doing three steps, 

Step 1:
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Step 2:
          Count lone pair of electron, each lone pair counts for s and p. In this case there is no lone pair of electron on carbon, so not included.

Step 3:
          Count single bonds for s and p. As we have already assigned s to the double bond, now one p for one single bond, and other p for the other single bond.

Result:
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                                                       Sp²

Practice:
You can practice for hybridization of Oxygen in this molecule. Oxygen has 2 lone pair of electrons. (Hint: Sp² Hybridization)
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