If I have 340 mL of a 1.5 M NaBr solution, what will the concentration be if I add 560 mL more water to it?
1 answer:
Answer:
0.5667 M ≅ 0.57 M.
Explanation:
It is known that the no. of millimoles of a solution before dilution is equal to the no. of millimoles of the solution after the dilution.
It can be expressed as:
(MV) before dilution = (MV) after dilution.
M before dilution = 1.5 M, V before dilution = 340 mL.
M after dilution = ??? M, V after dilution = 340 mL + 560 mL = 900 mL.
∴ M after dilution = (MV) before dilution/(V) after dilution = (1.5 M)(340 mL)/(900 mL) = 0.5667 M ≅ 0.57 M.
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