Wasnt sure if you were asking just for the standard form of that equation
<span>(15y − 9 + 6y^2) + (10 − 5y) = 0 ) or if you wanted the equation simplified and then in standard form ( 6y^2 + 10y + 1 = 6 ) so i did both </span>
=(D-64)2
We move all terms to the left:
-((D-64)2)=0
We calculate terms in parentheses: -((D-64)2), so:
(D-64)2
We multiply parentheses
2D-128
Back to the equation:
-(2D-128)
We get rid of parentheses
-2D+128=0
We move all terms containing D to the left, all other terms to the right
-2D=-128
D=-128/-2
D=+64
Answer:
It is one-half the area of a rectangle with sides 4 units × 3 units
Step-by-step explanation:
One side of the triangle is on the line y = 2 between points x=2 and x=6. So, that side has length 6-2 = 4.
The opposite vertex has y-value 5, so is 3 units away from the line y = 2.
The area of the triangle can be considered to have a base of 4 and a height of 3. In the formula ...
A = (1/2)bh
we find the area to be ...
A = (1/2)×(4 units)×(3 units) . . . . triangle area
__
A rectangle's area is the product of its length and width. So, a rectangle that is 4 units by 3 units will have an area of ...
A = (4 units)×(3 units) . . . . rectangle area
Comparing the two area formulas, we see that the triangle area is 1/2 the area of the rectangle with sides 4 units × 3 units.
