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3 years ago

Which layer of the sun do we normally see?

Physics

1 answer:

astra-53 [7]3 years ago

4 0

Answer: I think its called the "photosphere"

Explanation: Its very unsafe to look at but when you look up at the sun, visible lights radiates the sun so we can see it. Hope this helps!

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An acetal polymer block is fixed to the rigid plates at its top and bottom surfaces. If the top plate displaces 2 mm horizontall

Taya2010 [7]

Answer:

The shear modulus of the polymer is 5 MPa

Solution:

As per the question:

displacement of the top plate, d = 2 mm = 0.002 m

Horizontal Force, P = 2 kN = 2000 N

Width of the block, w = 100 mm = 0.1 m

By small angle analysis:

Angle, $\gamma = \frac{2}{200} = 0.01 rad$

Now,

Stress, $\tau$ = $\frac{P}{Area} = \frac{2000}{0.4\times 0.1} = 50000 Pa$

$G = \frac{\tau}{\gamma} = \frac{50000}{0.01} = 5 MPa$

3 0

3 years ago

Need a little help here, ASAP please. The subject is simple science, not physics.

JulsSmile [24]

Shape, because a liquid can have mass, volume, and color, but it cannot have a definitive shape

5 0

3 years ago

Two balls of mass m1 and m2, with velocities v1 and v2 collide head on. Is there any way for both balls to have zero velocity af

nordsb [41]

Answer:

Explanation:

As the final Kinetic energy is zero or less than initial kinetic energy, the collision must be inelastic.

In Inelastic collision both the bodies must stick together as final velocity is zero for both the bodies.

To conserve the momentum, momentum associated before the collision of first must be equal and opposite to the momentum associated with the second ball.

i.e.

$m_1v_1=m_2v_2$

8 0

4 years ago

A tiger leaps with a horizontal speed of 4.5 m/s from a boulder and lands 15 meters away.What is the vertical velocity with whic

Gelneren [198K]

Answer:

v_oy = 16.33 m/s

Explanation:

To find the vertical velocity of the tiger, you use the information about the horizontal velocity and maximum horizontal distance traveled.

You use the following formula for the range of the trajectory:

$x_{max}=\frac{2v_{ox}v_{oy}}{g}$ ( 1 )

v_ox: horizontal initial velocity = 4.5m/s

v_oy: vertical initial velocity = ?

g: gravitational acceleration = 9.8m/s^2

x_max: range of the trajectory = 15 m

You do v_oy the subject of the formula ( 1 ) and you replace the values of the other parameters in order to calculate v_oy:

$v_{oy}=\frac{gx_{max}}{2v_{ox}}=\frac{(9.8m/s^2)(15m)}{2(4.5m/s)}\\\\v_{oy}=16.33\frac{m}{s}$

hence, the initial vertical velocity of the tiger is 16.33m/s

8 0

3 years ago

A driver in a car speeding to the right at 24m/s suddenly hits the brakes and goes into a skid, finally coming to rest. The coef

irina [24]

Answer:

42 m

Explanation:

$v_{o}$ = initial velocity of the car = 24 m/s

$v_{f}$ = final velocity of the car = 0 m/s

μ = coefficient of kinetic friction = 0.7

g = acceleration due to gravity = 9.8 m/s²

a = acceleration due to kinetic frictional force = - μg = - (0.7)(9.8) = - 6.86 m/s²

d = distance through which the car skids

Using the kinematics equation

$v_{f}^{2} = v_{o}^{2} + 2 a d$

Inserting the values

$0^{2} = 24^{2} + 2 (- 6.86) d$

d = 42 m

8 0

3 years ago