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Ilia_Sergeevich [38]
3 years ago
10

A 110. g wooden block is initially at rest on a rough horizontal surface when a 12.8 g bullet is fired horizontally into (but do

es not go through) it. After the impact, the block–bullet combination slides 6.5 m before coming to rest. If the coefficient of kinetic friction between block and surface is 0.750, determine the speed of the bullet (in m/s) immediately before impact.
Physics
1 answer:
Taya2010 [7]3 years ago
8 0

Answer:

94 ms⁻¹

Explanation:

V = Speed of the bullet-block combination after collision

d = distance traveled by the combination before coming to stop = 6.5 m

\mu = Coefficient of kinetic friction = 0.750

acceleration due to friction on a flat surface can be given as

a = - \mu g = - (0.750) (9.8) = - 7.35 ms^{-2}

V_{f} = Final speed of the combination = 0 m/s

Based on the above equation , we can use the kinematics equation as

V_{f}^{2} = V^{2} + 2 a d\\(0)^{2} = V^{2} + 2 (- 7.35) (6.5)\\V = 9.8 ms^{-1}

M = mass of the wooden block = 110 g

m = mass of the bullet = 12.8 g

v = Speed of the bullet before collision

Using conservation of momentum for inelastic collision , we have

m v = (m + M) V\\(12.8) v = (12.8 + 110) (9.8)\\v = 94 ms^{-1}

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fiasKO [112]

Answer:

B. 1500 kg*m/s

Explanation:

Momentum p = m* v

In any type of collision, the total momentum is preserved!

The total momentum before and the total momentum after the collision is the same. We know the mass and speed after the collision so we can calculate the total momentum.

p1 + p2 =

m1*v1 + m2*v2

m1 = me = 300 kg

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Substitute the given numbers:

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900 + 600

1500 kg*m/s, which is answer B.

3 0
3 years ago
When a body of mass 0.25 kg is attached to a vertical massless spring, it is extended 5.0 cm from its unstretched length of 4.0
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Answer:

d=0.165m

Explanation:

Given

m=0.25kg,x_{1}=5cm*\frac{1m}{100cm}=0.05m,x_{2}=4cm*\frac{1m}{100cm}=0.04m,v=2\frac{rev}{s}

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But Fc is also

Fc=KxΔr

F_{c}=K*(r-x_{2})

Replacing

m*4\pi^2*r=K*(r-x_{2})

0.25kg*4\pi^2*r=49*(r-0.04m)

r=0.205m

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The PUPIL serves as the passage for light into the eye while in the camera, the APERTURE does the same.

The photosensitive surface in the eye is the YELLOW SPOT while in the camera, the photosensitive surface is the PHOTOGRAPHIC FILM.

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4 0
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matrenka [14]

True. Electromagnetic energy does not require a medium.

7 0
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