a. By definition of conditional probability,
P(C | D) = P(C and D) / P(D) ==> P(C and D) = 0.3
b. C and D are mutually exclusive if P(C and D) = 0, but this is clearly not the case, so no.
c. C and D are independent if P(C and D) = P(C) P(D). But P(C) P(D) = 0.2 ≠ 0.3, so no.
d. Using the inclusion/exclusion principle, we have
P(C or D) = P(C) + P(D) - P(C and D) ==> P(C or D) = 0.6
e. Using the definition of conditional probability again, we have
P(D | C) = P(C and D) / P(C) ==> P(D | C) = 0.75
Answer:
11
Step-by-step explanation:
Answer:
21
Step-by-step explanation:
subtract 3t from both sides
multiply both sides by 3
so 6t = -21
Answer:
valid based on the given information. If not, write invalid. ... So, the statement is invalid. Determine .....disprove a conjecture reached using inductive or deductive .
<span>D. One hundred random students from the sixth grade is the best choice given!
</span><span>
Reasons why the other answers and not good choices.
A. The first 100 students from an alphabetical list of the entire school, is incorrect because his only concern is the 6th graders, by including everyone he would negatively skew the data.
B. The first 100 students from an alphabetical list of sixth graders, is incorrect because its unfair to those with names starting later in the alphabet.
C. One hundred random students from the entire school </span>is is better but still incorrect because his only concern is the 6th graders, <span>by including everyone he would again negatively skew the data.</span>
