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Norma-Jean [14]
4 years ago
7

PLEASE HELP WILL GIVE THANKS, 5 STAR RATING, AND BRAINLIEST!!!!

Mathematics
1 answer:
FromTheMoon [43]4 years ago
6 0
So these are trig questions so for question 1 you have the opposite side and you are trying to find the adjacent side so you use tan = o/a . So therefore tan(67) = 17/a so 17/tan(67) is a so a is 7.216 which is 7.2 to the nearest tenth.

For question 2 you have the adjacent side and are trying to find the opposite side so you do tan(24) is x/12 so tan(24) x 12 is x so x is 5.34 or 5.3 to the nearest tenth.

Question three you have the adjacent and are trying to find the opposite so you do tan(72) = x/20 so you do tan(72) x 20 to get 61.55 or 61.6 to the nearest tenth.
Hope this helps :)
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Answer:

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> a

[1] 51.72213 53.09989 59.89221 32.44023 47.59386 33.59892 47.26718 55.61510 47.95505 48.19296 54.46905

[12] 45.78072 57.30045 57.91624 50.83297 52.61790 62.07713 53.75661 49.34651 53.01501

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> sqrt(var(a))

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Step-by-step explanation:

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And we can use the following code: rnorm(20,50,6) and we got this output:

> a<-rnorm(20,50,6)

> a

[1] 51.72213 53.09989 59.89221 32.44023 47.59386 33.59892 47.26718 55.61510 47.95505 48.19296 54.46905

[12] 45.78072 57.30045 57.91624 50.83297 52.61790 62.07713 53.75661 49.34651 53.01501

Then we can find the mean and the standard deviation with the following formulas:

> mean(a)

[1] 50.72451

> sqrt(var(a))

[1] 7.470221

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3 years ago
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