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Lorico [155]
4 years ago
9

ASAP!! please What is the answer? MCQ. Thank you

Physics
2 answers:
sdas [7]4 years ago
8 0

Answer:

Id say C

Explanation:

The hypotenuse for c is up and to the right so the unit vectors show that

siniylev [52]4 years ago
3 0

Answer:

Option c

Explanation:

The diagram which follow" head to tail rule" show equilibrium

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5. A belt runs on a wheel of 30.0-cm radius. During the time that the wheel coasts uniformly to rest from an initial speed of 2.
emmasim [6.3K]

Answer:

Angular acceleration = 0.95rad/s

Number or revolution is 13

Explanation:

See attached file

5 0
3 years ago
Can any one help plz in the question ?
kherson [118]

Yes, No, yes

mark me brainliestttt :)))

5 0
3 years ago
Read 2 more answers
Help Please fast like now!!​
defon

Answer: d. availability of places to play

Explanation: I think that it’s d because availability of space to do your physical activity is important. Availabilty of places to play is an environmental factor due to where you decide to play.

7 0
3 years ago
An artillery shell is fired with an initial speed of 300m/s at 55 deegry about the horizontal,it explodes on a mountain side 42s
photoshop1234 [79]

Answer:

x = 7226.94 m

y = 1677.4 m

Explanation:

This is a classic problem of a parabolic move. Let's analyze the given data.

The speed is 300 m/s but it's fired at 55°, so the x and y component of the speed would be:

Vx = 300 cos55 = 172.07 m/s

Vy = 300 sin55 = 245.75 m/s

Now, to get the x and y components of the shell, we need to apply the following expressions:

X = Xo + Vx*t    (1)

Y = Yo + Vy*t - 1/2 gt²   (2)

Xo and Yo is 0, and we already have the speed in x and y, so the components are:

X = 0 + (172.07)(42)

<h2>X = 7226.94 m</h2>

For the y component:

Y = 0 + (245.75)(42) - 1/2 (9.8)(42)²

Y = 10321.5 - 8643.6

<h2>Y = 1677.4 m</h2><h2></h2>

Hope this helps

8 0
3 years ago
Point charges of 28.0 µC and 42.0 µC are placed 0.500 m apart. (a) At what point (in m) along the line connecting them is the el
olga_2 [115]

Answer: a) electric field will be zero at zero meters apart

b) for smaller charge q, E = 6.048X10^6N/m towards away from the charge,

for bigger charge Q, E = 4.032X10^6N/m

Explanation:

Detailed explanation and calculation is shown in the image below.

6 0
3 years ago
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