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ivanzaharov [21]
2 years ago
8

Which of the following is not a longitudinal

Physics
2 answers:
timurjin [86]2 years ago
5 0

Light waves are transverse waves, but sound waves and Ultrasound waves belongs to longitudinal waves category.

so, correct choice is :

  • Light waves
Ipatiy [6.2K]2 years ago
4 0

Answer:

light waves is not a longitudinal wave.

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An inattentive driver is traveling 18.0 m/s when he notices a red light ahead. his car is capable of decelerating at a rate of 3
ryzh [129]

Speed of the car given initially

v = 18 m/s

deceleration of the car after applying brakes will be

a = 3.35 m/s^2

Reaction time of the driver = 0.200 s

Now when he see the red light distance covered by the till he start pressing the brakes

d_1 = v* t

d_1 = 18* 0.200 = 3.6 m

Now after applying brakes the distance covered by the car before it stops is given by kinematics equation

v_f^2 - v_i^2 = 2 a s

here

vi = 18 m/s

vf = 0

a = - 3.35

so now we will have

0^2 - 18^2 = 2*(-3.35)(s)

s = 48.35 m

So total distance after which car will stop is

d = d_1 + d_2

d = 48.35 + 3.6 = 51.95 m

So car will not stop before the intersection as it is at distance 20 m

3 0
3 years ago
What are the coefficients in this expression?
skad [1K]

6 and \frac{1}{3}

Explanation:

The expression:

     6a - \frac{3}{4}  + 7.5 - \frac{b}{3}

 A coefficient is a numerical constant usually placed before a variable in an expression.

They are used to multiply variables.

 Given equation is;

   6a - \frac{3}{4}  + 7.5 - \frac{b}{3}

There are two variables in this expression which are;

  a and  - b

  6 (a) - \frac{3}{4}  + 7.5 - b (\frac{1}{3} )

The coefficients in this expression are:

    6 and \frac{1}{3}

learn more:

Quadratic equation brainly.com/question/1357167

#learnwithBrainly

7 0
3 years ago
Read 2 more answers
If the strings have the same thickness but different lengths, which of the following parameters, if any, willbe different in the
Vinil7 [7]

Answer:

If the strings have same thickness but different lengths then these parameters wave frequency, speed, wavelength will be different in the two strings. so the option d) None of the above is correct.

Explanation:

5 0
3 years ago
Blocks A (mass 3.50 kg) and B (mass 6.50 kg) move on a frictionless, horizontal surface. Initially, block B is at rest and block
Vedmedyk [2.9K]

Answer:

(a) V (A) =  0.7 m/s,

(b) V (A) =  0.7 m/s,

(c) V (B) =  0.7 m/s

(d) u= - 0.60 m/s

(e) v = 0.75 m/s

Explanation:

Given:

M(A) =3.50 Kg, M(B)=6.50 Kg, V(A) = 2.00 m/s, V(B) = 0 m/s

Sol:

a)  law of conservation of momentum

M(a) x V(A) + M(B) x V(B) = ( M(a) + M(B) ) V      (let V is Common Velocity of Both block)

so 3.50 Kg x 2.00 m/s + 6.50 Kg x 0 m/s = (3.50 Kg + 6.50 Kg ) V

after solving V =  0.7 m/s

After the collision the velocities of the both block will be as the the spring is compressed maximum.

V (A) =  0.7 m/s

b)  V(A) =  0.7 m/s ( Part (a) and Part (a) are repeated )

c) as stated above the in the Part (a)

V(B) =  0.7 m/s

d) When the both blocks moved apart after the collision:

Let u=velocity of block A after the collision.

and v = velocity of block B after the collision.

then conservation of momentum

M(a) x V(A) + M(B) x V(B) = M(a) x v + M(B) x u

⇒ 3.50 Kg x 2.00 m/s + 6.50 Kg x 0 m/s =  3.50 Kg x u + 6.50 Kg x v

⇒ 2.00 m/s = u + 1.86 v -----eqn (1)  ( dividing both side by 3.50 Kg)

For elastic collision  

the velocity relative approach = velocity relative separation

so 2.00 m/s = v-u  ----- eqn (2)

⇒v = u + 2.00 m/s

putting this value in eqn (1) we get

2.00 m/s = u + 1.86 (v + 2.00 m/s)

u= - 0.60 m/s

e) putting v= 2.00 m/s in eqn (1)

2.00 m/s = - 2.32 m/s + 1.86 v

v = 0.75 m/s

5 0
3 years ago
How does the speed of light compare to the speed of sound?
Lelu [443]
Light is faster. Humans can travel faster than sound, however not light- nothing seems to go faster than 3×10∧8 meters per second.
7 0
3 years ago
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