Avg acceleration; under constant acceleration condition only; = Vf-Vi/time
a=Vf-Vi/time=(15m/s-6m/s)/(3s)=
(9m/s)/(3s)=3m/s^2
Hope this helps. Thanks.
Answer:
one-third of its weight on Earth's surface
Explanation:
Weight of an object is = W = m*g
Gravity on Earth = g₁ = 9.8 m/s
Gravity on Mars = g₂ = 
g₁
Weight of probe on earth = w₁ = m * g₁
Weight of probe on Mars = w₂ = m * g₂ -------- ( 1 )
As g₂ = g₁/3 --------- ( 2 )
Put equation (2) in equation (1)
so
Weight of probe on Mars = w₂ = m * g₁ /3
Weight of probe on Mars = m * g₁ = w₁
⇒Weight of probe on Mars = Weight of probe on earth
Answer: The speed limit is 15 mph when you come within 100 feet of a railroad crossing and you cannot see the tracks for 400 feet in both directions. You may go faster than 15 mph if the crossing is controlled by gates, a warning signal, or a flagman.
Explanation: hope this helps
Answer:
Newton's insight on the inverse-square property of gravitational force was from intuition about the motion of the earth and the moon. The mathematical formula for gravitational force is F=GMmr2 F = G Mm r 2 where G .
Explanation:
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It increases, because the centripetal acceleration is inversely proportional to the radius of the curvature.
Hopr it helps :)
