Force=mass x acceleration
f= 0.5 x40
f=20N
Answer:
Empirical formula
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Answer:
32km per hour
Explanation:
Explanation:
In first case v = a t
==> a t = 40 km p h
Now distance covered S1 + S2 + S3
S1 = 1/2 a t^2 and S3 = 1/2 a t^2
But S2 = 3t * 40 = 120 t km
Hence total distance = at^2 + 120 t
Time taken (total) = t + 3t + t = 5 t
Hence average speed = at^2 + 120 t / 5 t
Cancelling t we have at + 120 / 5 = 40 + 120 / 5 = 160/5 = 32 km per hour
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Answer:
Tangential speed, v = 2.64 m/s
Explanation:
Given that,
Mass of the puck, m = 0.5 kg
Tension acting in the string, T = 3.5 N
Radius of the circular path, r = 1 m
To find,
The tangential speed of the puck.
Solution,
The centripetal force acting in the string is balanced by the tangential speed of the puck. The expression for the centripetal force is given by :
v = 2.64 m/s
Therefore, the tangential speed of the puck is 2.64 m/s.
