The distance of BF is 7.07
Answer:
21 ft by 66 ft
Step-by-step explanation:
From the question,
P = 2(L+W)............... Equation 1
Where P = Perimeter of the playing Field, L = Length of the playing Field, W = width of the playing Field.
If the Length of the Field is 45 ft longer than the width,
L = 45+W............ Equation 2
Substitute Equation 2 into equation 1
P = 2(45+W+W)
P = 90+4W............. Equation 3
Given: P = 174 ft.
Substitute into equation 3
174 = 90+4W
4W = 174-90
4W = 84
W = 84/4
W = 21 ft.
Substituting the value of W into equation 2
L = 45+21
L = 66 ft.
Hence the dimensions of the playing field is 21 ft by 66 ft
Answer:
x=45
Step-by-step explanation:
Then,
x/5(15)-47=28
Step 1: Simplify the equation on both sides
x/9(15)-47=28
5/3x-47=28
Step 2: Add 47 to both sides
5/3x-47+47=28+47
5/3x=75
Step 3: Multiply both sides by 3/5
(3/5)*(5/3x)=(3/5)*(75)
x=45
Answer:
C.
Step-by-step explanation:
5z - 7, you would say 5 times z minus 7, which is the same as 5 less than th product of 7 and a number z
