Answer:
As few as just over 345 minutes (23×15) or as many as just under 375 minutes (25×15).
Imagine a simpler problem: the bell has rung just two times since Ms. Johnson went into her office. How long has Ms. Johnson been in her office? It could be almost as short as just 15 minutes (1×15), if Ms. Johnson went into her office just before the bell rang the first time, and the bell has just rung again for the second time.
Or it could be almost as long as 45 minutes (3×15), if Ms. Johnson went into her office just after the bells rang, and then 15 minutes later the bells rang for the first time, and then 15 minutes after that the bells rang for the second time, and now it’s been 15 minutes after that.
So if the bells have run two times since Ms. Johnson went into her office, she could have been there between 15 minutes and 45 minutes. The same logic applies to the case where the bells have rung 24 times—it could have been any duration between 345 and 375 minutes since the moment we started paying attention to the bells!
Step-by-step explanation:
the answer would be E because if you round answer E to 3mph and divide by 2 you get 1.5 and a hour is 60 minutes divide that by 2 and you get 30 minutes however you walked slightly slower so it would take 5 minutes longer.
Answer:
Below.
Step-by-step explanation:
The number of combinations of 7 from 32 = 32! / 7! (32-7)!
= 3365856
So it is 1/ 3365856 = 0.000000297
or about 3 in 10,000,000.
Answer:
the tenths and the thousands
