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GenaCL600 [577]
3 years ago
15

Which is the correct Lewis dot structure of NH2-?

Chemistry
2 answers:
zavuch27 [327]3 years ago
8 0

Answer: The correct answer is Option D.

Explanation:

Lewis dot structures are the structures which represent the valance electrons of an element forming a compound. The electrons are represented as the dots.

In a compound, the bonded electrons are represented as a bond and lone pair of electrons are represented as dots.

In NH_2^- compound,

Electronic configuration of Nitrogen: 1s^22s^2p^3

Valence electrons in nitrogen = 5

Electronic configuration of hydrogen: 1s^1

Valence electrons in hydrogen = 1

In the given compound, bond pairs are 2 which means number of electrons bonded are 4.

Unbonded electrons left on nitrogen will be 3 and this compound has an extra electron because of the negative charge present on the compound. Hence, total unbonded electrons present on this compound will be 4.

Therefore, the lewis dot structure will be Option D.

3241004551 [841]3 years ago
6 0
D. The total number of valence electrons is 8 and D represents that. D also correctly uses the octet rule for N and duet rule for H.
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The composition of a liquid-phase reaction 2A - B was monitored spectrophotometrically. The following data was obtained: t/min 0
o-na [289]

Answer:

1) The order of the reaction is of FIRST ORDER

2)   Rate constant k = 5.667 × 10 ⁻⁴

Explanation:

From the given information:

The composition of a liquid-phase reaction 2A - B was monitored spectrophotometrically.

liquid-phase reaction 2A - B signifies that the reaction is of FIRST ORDER where the rate of this reaction is directly proportional to the concentration of A.

The following data was obtained:

t/min                    0         10         20          30             40          ∞

conc B/(mol/L)    0       0.089    0.153     0.200       0.230    0.312

For  a first order reaction:

K = \dfrac{1}{t} \ In ( \dfrac{C_{\infty} - C_o}{C_{\infty} - C_t})

where :

K = proportionality  constant or the rate constant for the specific reaction rate

t = time of reaction

C_o = initial concentration at time t

C _{\infty} = final concentration at time t

C_t = concentration at time t

To start with the value of t when t = 10 mins

K_1 = \dfrac{1}{10} \ In ( \dfrac{0.312 - 0}{0.312 - 0.089})

K_1 = \dfrac{1}{10} \ In ( \dfrac{0.312 }{0.223})

K_1 =0.03358 \  min^{-1}

K_1 \simeq 0.034 \  min^{-1}

When t = 20

K_2= \dfrac{1}{20} \ In ( \dfrac{0.312 - 0}{0.312 - 0.153})

K_2= 0.05 \times  \ In ( 1.9623)

K_2=0.03371 \ min^{-1}

K_2 \simeq 0.034 \ min^{-1}

When t = 30

K_3= \dfrac{1}{30} \ In ( \dfrac{0.312 - 0}{0.312 - 0.200})

K_3= 0.0333 \times  \ In ( \dfrac{0.312}{0.112})

K_3= 0.0333 \times  \ 1.0245

K_3 = 0.03412 \ min^{-1}

K_3 = 0.034 \ min^{-1}

When t = 40

K_4= \dfrac{1}{40} \ In ( \dfrac{0.312 - 0}{0.312 - 0.230})

K_4=0.025 \times  \ In ( \dfrac{0.312}{0.082})

K_4=0.025 \times  \ In ( 3.8048)

K_4=0.03340 \ min^{-1}

We can see that at the different time rates, the rate constant of k_1, k_2, k_3, and k_4 all have similar constant values

As such :

Rate constant k = 0.034 min⁻¹

Converting it to seconds ; we have :

60 seconds = 1 min

∴

0.034 min⁻¹ =(0.034/60) seconds

= 5.667 × 10 ⁻⁴ seconds

Rate constant k = 5.667 × 10 ⁻⁴

4 0
3 years ago
when performing solubility studies, why you should use deionized or distilled water rather than tap water?
Cerrena [4.2K]

Answer:

The science project or the proposed test using the water as a control element in the experiment determines whether you choose to use deionized water or distilled water. Of the two, distilled water is the purest because the water undergoes boiling that kills off most organic contaminants.

Explanation:

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5 0
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Can someone please help me figure this out
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use the equation PV=nRT and solve the problem

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