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GenaCL600 [577]
3 years ago
15

Calculate the volume of a sample of gas at 5.75 atm if it occupies 5.14 L at 2.49 atm

Chemistry
1 answer:
Ksivusya [100]3 years ago
4 0
Boyle's Law

Pressure 1 × Volume 1 = Pressure 2 × Volume2

or P1×V1= P2×V2

Finding Volume 2

(5.75atm)(5.14L) = (2.49atm)(V2)

Then Multiply

29.55atm•L = 2.49atm(V2)

Divided by 2.49

29.56atm•L / 2.49atm = 2.49atm(V2) / 2.49atm

V2= 11.87 L


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Answer:

Covalent Bond

Explanation:

In the diagram Carbon and each of the 4 Hydrogens are sharing electrons. They are also both non metals. Both of these are characteristics of Covalent Bonds.

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3 years ago
Write a balanced chemical equation for the standard formation reaction of liquid acetic acid hch3co2.
Afina-wow [57]

The balanced chemical equation for the standard formation reaction of liquid acetic acid is given as ,

2C(gr) +2H_{2} (g) +O_{2} (g)  → CH_{3} COOH(l)

The reaction that form the products from their elements in their standard state is called formation of reaction .The acetic acid consist C , H , and O , So, determine their standard state . Carbon is graphite at 25°C and 1 atm , whereas hydrogen and oxygen are diatomic gases . Hence , we start with unbalanced reaction.

C(gr) +H_{2} (g) +O_{2} (g) → CH_{3} COOH(l)

The balanced chemical equation for the standard formation reaction of liquid acetic acid as,

2C(gr) +2H_{2} (g) +O_{2} (g)  → CH_{3} COOH(l)

The combustion of liquid acetic acid is given as,

CH_{3} COOH(l) + 2O(g) → 2CO_{2}((g) +2H_{2} O(l)                    ΔH =-873

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5 0
2 years ago
What is the primary cause of diffusion? some substances can dissolve in solvents heat added to a substance random internal motio
Nina [5.8K]

Answer:

random internal motion of atoms and molecule

Explanation:

The primary cause of diffusion is the random internal motion of atoms and molecules.

Randomness of atoms and molecules results in diffusion.

  • Diffusion is the movement of particles from a region of high concentration to that of lower concentration.
  • Substances often tend to spread out over the concentration gradient.
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3 0
3 years ago
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KengaRu [80]

Covalent bonds can be classified as nonpolar and polar covalent given the electronegativity difference between two atoms (ΔEN).

Nonpolar covalent bond electrons are shared equally between two atoms, polar covalent bond electrons are shared unequally, atoms have partial charges, ionic bond electrons are completely transferred to one atom, full charges present. Therefore, the greater the electronegativity difference, the greater the bond polarity. Let's determine the types of bonds present in the compounds and arrange the ones with polar covalent in order of increasing ΔEN. Sulfur and oxygen are both nonmetals so the substance is covalent. Sulfur has EN = 2.5 and oxygen has EN = 3.5. Since there is an electronegativity difference, the S−O bonds in the substance can be classified as polar covalent bonds.

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3 0
2 years ago
Round to 3 significant figures 78.6500
cupoosta [38]

Answer:

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The number has 4 significant figures: 7,8 6 and 5.

To round off to 3 significant figures, the target digit is the third significant figure in the number.The determining digit is the fourth significant figure in the number; it is 5 hence the target digit will go up by 1 and any digits to the right of it will be rounded down to 0.

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