All categories

2 years ago

What species in the food web feed on algae?

Chemistry

1 answer:

Tomtit [17]2 years ago

6 0

Answer:

frogs, fish and aquatic (water-dwelling) insects

Explanation:

You might be interested in

What do you think could be happening to the sand eels

Alex777 [14]

Answer:

is there like a passage to answer this question?

Explanation:

7 0

3 years ago

Read 2 more answers

what Is the number of photons in one J of red light (650 nm) greater than, equal to, or less than the number of photons in one J

valentinak56 [21]

For the same amount of energy, the number of photons in red light will be greater than the number of photons in blue light.
This is because the energy carried by a photon is inversely proportional to the wavelength of the photon. A longer wavelength means there is a lower energy in the photons and a shorter wavelength means that there is a higher energy. Therefore, in order for the photons to deliver one joule of energy, more of the red light photons will be required.

7 0

2 years ago

Question 11 (3 points)

Ugo [173]

Answer:

The outer core of the earth is liquid.

Explanation:

Seismic waves travel through the Earth at different speeds and are reflected and refracted diffracted differently as they encounter layers of different densities.

By analyzing these waves, they have concluded that there is an inner core of solid iron surrounded by a liquid outer core consisting of nickel and iron.

A is wrong. The Earth consists of several layers

C is wrong. Seafloor spreading is caused by the movement of tectonic plates away from each other.

D is wrong. The mantle is mostly solid rock.

4 0

3 years ago

While ethanol (CH3CH2OH) is produced naturally by fermentation, e.g. in beer- and wine-making, industrially it is synthesized by

grin007 [14]

Answer:

$n_{C2H_5OH}^{eq}=14.234mol$

Explanation:

Hello,

In this case, the reaction is:

$C_2H_4+H_2O\rightleftharpoons CH_3CH_2OH$

Thus, the law of mass action turns out:

$Kc=\frac{[CH_3CH_2OH]_{eq}}{[H_2O]_{eq}[CH_2CH_2]_{eq}}$

Thus, since at the beginning there are 29 moles of ethylene and once the equilibrium is reached, there are 16 moles of ethylene, the change $x$ result:

$[CH_2CH_2]_{eq}=29mol-x=16mol\\x=29-16=13mol$

In such a way, the equilibrium constant is then:

$Kc=\frac{\frac{x}{V} }{\frac{16mol}{V}* \frac{3mol}{V}} =\frac{\frac{13mol}{75.0L} }{\frac{16mol}{75.0L}* \frac{3mol}{75.0L}} =20.31$

Thereby, the initial moles for the second equilibrium are modified as shown on the denominator in the modified law of mass action by considering the added 15 moles of ethylene:

$Kc=\frac{\frac{13+x_2}{V} }{\frac{16+15-x_2}{V}* \frac{3-x_2}{V}} =20.31$