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3 years ago

What precautions should you take when working with electronic equipment?

Physics

1 answer:

ollegr [7]3 years ago

7 0

Answer:

Be sure to unplug the power source of all electrical equipment before working on it. Always pull from the plug, not the cord. Always wear proper non conductive clothing – insulated gloves, non conductive protective apparel and shoes with insulated soles. Avoid loose clothing or ties.

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A 755 N force is used to push a 15 Kg box across the floor. What is the acceleration of the box?

cluponka [151]

Answer:

good question!

Explanation:

3 0

3 years ago

Read 2 more answers

2. Two cars A and B are heading forward. The velocity of A and B are 30 m/s and 20 m/s

KengaRu [80]

Answer:

A.) 27000 kgm/s

18000 kgm/s

B.) Va = 22 m/s

C.) 19800 kgm/s

25200 kgm/s

Explanation: Given that the velocity of A and B are 30 m/s and 20 m/s. And of the same mass M = 9 × 10^5g

M = 9×10^5/1000 = 900 kg

A.) Initial momentum of A

Mu = 900 × 30 = 27000 kgm/s

Initial momentum of B

Mu = 900 × 20 = 18000 kgm/s

B.) if they have an accident and then the velocity of the B is 28 m/s, find out velocity of A.

Momentum before impact = momentum after impact

Given that Vb = 28 m/s

27000 + 18000 = 900Va + 900 × 28

45000 = 900Va + 25200

900Va = 45000 - 25200

900Va = 19800

Va = 19800/900

Va = 22 m/s

C.) Momentum of A after impact

MV = 900 × 22 = 19800 kgm/s

Momentum of B after impact

MV = 900 × 28 = 25200 kgm/s

8 0

3 years ago

A charged capacitor is connected to an ideal inductor. At time t = 0, the charge on the capacitor is equal to 6.00 μC. At time t

Len [333]

Answer:

$4.71\times 10^{-3}A$

Explanation:

$Q_{max}$ = Maximum charge stored by capacitor = 6 μC = 6 x 10⁻⁶ C

$t$ = time taken for charge on the capacitor to become zero = 2 ms = 2 x 10⁻³ s

Time period is given as

$T = 4t$

$T = 4(2\times 10^{-3})$

$T = 8\times 10^{-3} s$

Angular frequency is given as

$w = \frac{2\pi }{T}$

$w = \frac{2(3.14) }{8\times 10^{-3}}$

$w$ =785 rad/s

Charge at any time is given as

$Q(t) = Q_{max}Coswt$

Taking derivative both side relative to "t"

$\frac{\mathrm{d}Q(t) }{\mathrm{d} t} = \frac{\mathrm{d}(Q_{max}Coswt) }{\mathrm{d} t}$

$i(t)= -Q_{max} w Sinwt$

Amplitude of the current is given as

$i_{max}= Q_{max} w$

$i_{max}= (6\times 10^{-6}) (785)$

$i_{max}= 4.71\times 10^{-3}A$

8 0

3 years ago

A pair of slits, separated by 0.150 mm, is illuminated by light having a wavelength of λ = 643 nm. An interference pattern is ob

kumpel [21]

Answer:

0.006 m

Explanation:

d = separation between the slits = 0.150 mm = 0.150 x 10⁻³ m

λ = wavelength of the light = 643 nm = 643 x 10⁻⁹ m

D = distance of the screen where interference pattern is observed = 140 cm = 1.40 m

δ = Path difference

Path difference is given as

δ = Dλ/d

δ = (1.40) (643 x 10⁻⁹)/(0.150 x 10⁻³)

δ = 0.006 m

3 0

3 years ago

What are flavonoids responsible ?

Travka [436]

Answer:

<h3>Flavonoids are a diverse group of phytonutrients (plant chemical) found in almost all fruits and vegetables. Along with carotenoids they are Responsible for the vivid color in fruit and vegetables. .... Like other phytonutrients flavonoids are powerful antioxidant with anti-inflammatory and immune system benefits.</h3>

6 0

3 years ago