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adoni [48]
3 years ago
13

Rank the pressures from highest to lowest:

Physics
1 answer:
n200080 [17]3 years ago
3 0

Answer:

P₃ > P₁ > P₂

Explanation:

To rank pressure of the given situation

a) we know

  Pressure at height h below

      P = ρ g h

density of salt water, ρ = 1029 kg/m³

      P₁ = 1029 x 10 x 0.2

      P₁ = 2058 Pa

b) density of fresh water, ρ = 1000 kg/m³

      P₂ = 1000 x 10 x 0.2

      P₂ = 2000 Pa

c) density of mercury, ρ = 13593 kg/m³

      P₃ = 13593 x 10 x 0.05

      P₃ = 6796.5 Pa

Rank of Pressures from highest to lowest

        P₃ > P₁ > P₂

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3 years ago
A horizontal spring with stiffness 0.4 N/m has a relaxed length of 11 cm (0.11 m). A mass of 21 grams (0.021 kg) is attached and
riadik2000 [5.3K]

Answer:

0.6983 m/s

Explanation:

k = spring constant of the spring = 0.4 N/m

L₀ = Initial length = 11 cm = 0.11 m

L = Final length = 27 cm = 0.27 m

x = stretch in the spring = L - L₀ = 0.27 - 0.11 = 0.16 m

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v = speed of the mass

Using conservation of energy

Kinetic energy of mass = Spring potential energy

(0.5) m v² = (0.5) k x²

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5 0
3 years ago
The atoms in a sidewalk on a hot summer day are vibrating _____ the atoms in the sidewalk on a freezing day in winter.
Karolina [17]

Answer:

(A) more rapidly than

Explanation:

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7 0
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A heavy ball with a weight of 150 N is hung from the ceiling of a lecture hall on a 4.1-m-long rope. The ball is pulled to one s
AlladinOne [14]

Answer:

The tension in the rope is 262.88 N

Explanation:

Given:

Weight W = 150 N

Length of rope r = 4.1 m

Initial speed of ball v = 5.5 \frac{m}{s}

For finding the tension in the rope,

First find the mass of rod,

mg = 150                          ( g = 9.8 \frac{m}{s^{2} } )

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Tension in the rope is,

  T = mg + \frac{mv^{2} }{r}

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  T = 262.88 N

Therefore, the tension in the rope is 262.88 N

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3 years ago
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