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adoni [48]
3 years ago
13

Rank the pressures from highest to lowest:

Physics
1 answer:
n200080 [17]3 years ago
3 0

Answer:

P₃ > P₁ > P₂

Explanation:

To rank pressure of the given situation

a) we know

  Pressure at height h below

      P = ρ g h

density of salt water, ρ = 1029 kg/m³

      P₁ = 1029 x 10 x 0.2

      P₁ = 2058 Pa

b) density of fresh water, ρ = 1000 kg/m³

      P₂ = 1000 x 10 x 0.2

      P₂ = 2000 Pa

c) density of mercury, ρ = 13593 kg/m³

      P₃ = 13593 x 10 x 0.05

      P₃ = 6796.5 Pa

Rank of Pressures from highest to lowest

        P₃ > P₁ > P₂

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The  pressure is  P =   1652 \  Pa

Explanation:

From the question we are told that

    The  volume of the container is  V  =  1.83  \ L =  1.83 *10^{-3 } \  m^3

     The mass of  N_2 is  m_n  =  0.246 \ g =  0.246 *10^{-3} \ kg

     The root-mean-square velocity is  v =  192 \ m/s

The  root -mean square velocity is mathematically represented as

      v =  \sqrt{ \frac{3 RT}{M_n  } }

Now the ideal gas law is mathematically represented as

      PV  =  nRT

=>   RT  =  \frac{PV}{n }

Where n is the number of moles which is mathematically represented as

         n =  \frac{ m_n }{M }

Where  M  is the molar mass of  N_2

So  

        RT  =  \frac{PVM_n }{m _n  }

=>    v =  \sqrt{ \frac{3 \frac{P* V  *  M_n }{m_n } }{M_n  } }

=>    v =  \sqrt{  \frac{ 3 *  P* V  }{m_n } } }

=>   P =   \frac{v^2   *  m_n}{3 *    V  }

substituting values

    =>    P =   \frac{( 192)^2   *  0.246 *10^{-3}}{3 *    1.83 *10^{-3} }

=>         P =   1652 \  Pa

       

     

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