Answer: t = 10s
Explanation:
Assuming there's no air resistance,
Initial velocity (u) = 0 m/s
Acceleration by gravity (a) = 9.81 m/s^2
Displacement (s) = 500m
Time taken (t) = ?
Now,
Use formula,
s = u×t + (1/2)×a×t^2
s = 0×t + (1/2)×9.81×t^2
500 = 4.905×t^2
t = 10s
<h2>
Height of cliff is 66.43 meter.</h2>
Explanation:
Consider the horizontal motion of shell,
We have equation of motion s = ut + 0.5 at²
Initial velocity, u = 1770 m/s
Acceleration, a = 0 m/s²
Displacement, s = 6520 m
Substituting
s = ut + 0.5 at²
6520 = 1770 x t + 0.5 x 0 xt²
t = 3.68 s
Time of flight of shell = 3.68 s.
Now consider the vertical motion of shell,
We have equation of motion s = ut + 0.5 at²
Initial velocity, u = 0 m/s
Acceleration, a = 9.81 m/s²
Time, t = 3.68 s
Substituting
s = ut + 0.5 at²
s = 0 x 3.68 + 0.5 x 9.81 x 3.68²
s = 66.43 m
Height of cliff is 66.43 meter.
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