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Finger [1]
2 years ago
12

In the diagram, line p is parallel to line q. What is the value of x and y? (NEED HELP)

Mathematics
1 answer:
hichkok12 [17]2 years ago
4 0

Y is 42°

The x is not the picture

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!!!!HELP NEEDED!!!!
Svetllana [295]

It is true that the product of two consecutive even integers are always one less than the square of their average.

<u>Step-by-step explanation</u>:

Let the two consecutive odd integers be 1 and 3.

  • The product of 1 and 3 is (1\times3)=3
  • The average of 1 and 3 is (1+3)/2 =4/2 = 2
  • The square of their average is (2)² = 4

∴ The product 3 is one less than the square of their average 4.

Let the two consecutive even integers be 2 and 4.

  • The product of 2 and 4 is (2\times4)=8
  • The average of 2 and 4 is (2+4)/2 =6/2 = 3
  • The square of their average is (3)² = 9

∴ The product 8 is one less than the square of their average 9.

Thus, It is true that the product of two consecutive even integers are always one less than the square of their average.

4 0
3 years ago
wind speed varies in the first twenty meters above the ground. for a particular day, let f(x)=4.5ln x = 6.5 compute the wind spe
kakasveta [241]

Answer:

it is d

Step-by-step explanation:

4 0
3 years ago
I Dont understand what to do
Sati [7]
You need to find the area of this
4 0
3 years ago
Question 2: What is the volume of this prism?
laiz [17]

Answer:

42 cubic units

Step-by-step explanation:

2x3x7

6 0
2 years ago
If an object is launched at an angle of 28° with an initial velocity of 133 ft./s from a height of 6 feet how many seconds will
Tema [17]

Answer:

Hence after  3.98 sec  i.e  4 sec Object will hit the ground  .

Step-by-step explanation:

Given:

Height= 6 feet

Angle =28 degrees.

V=133 ft/sec

To Find:

Time in seconds after which it will hit the ground?

Solution:

<em>This problem is related to projectile motion for objec</em>t

First calculate the Range for object  and it is given by ,

R=v^2Sin(2Ф)/g

Here R= range  g= acceleration due to gravity =9.8 m/sec^2

1m =3.2 feet

So 9.8 m, equals to 9.8 *3.2=31.36 ft

So g=31.36 ft/sec^2. and 2Ф=2(28)=56

R=133^2*Sin(56)/31.36

R=14664.84/31.36

R=467.62  fts

Now using Formula for time and range as

R=VxT

Vx is horizontal velocity

Vx=V*cosФ

Vx=133*cos(28)

Vx=117.43  ft/sec

So above equation becomes as ,

467.62=117.43*T

T=467.62/117.43

T=3.98 sec

T is approximately equals to 4 sec.

4 0
3 years ago
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