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erik [133]
2 years ago
14

How can distributive property be used to solve 7 x 391

Mathematics
1 answer:
Advocard [28]2 years ago
7 0

Answer:

7x ³⁹¹

Step-by-step explanation:

1: "x3" was replaced by "x^3".

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Solve this problem using the Distributive Property.<br><br> 2 ( 7 + 8 ) =
maria [59]

Answer:

30

Step-by-step explanation:

Original Equation: 2(7 + 8)

So you have to multiply 2 by 7 which equals 14

Then you multiply 2 by 8 which equals 16

Your equation should now look like this: 14 + 16

Add 14 and 16 together.

Your answer is 30

Hope I helped :)

Please condsider brainliest

7 0
3 years ago
I need help with this question
blsea [12.9K]
1....2470, 2474

2....2471,2473,2477

3.....340, 341, 342, 343, 344

7 0
3 years ago
The stock at Z-Mart was 2,500 items. The stock went down 10% after the weekend. On Wednesday, 10% more stock was added. How many
crimeas [40]
2500 * 0.9 = 2250
2250 * 0.9 = 2025 current stock
7 0
3 years ago
What is 5 1/9 - 2 5/9 equal​
stich3 [128]

I think it’s 2 5/9. You might want someone to double check it, though.

4 0
3 years ago
Read 2 more answers
The safe load, L, of a wooden beam supported at both ends varies jointly as the width, w, and the square of the depth, d, and in
MakcuM [25]

Answer:

joint variation means L (safe load) is directly proportional to both w and d2

inverse proportionality means L = k/l

So the equation is:

L = k(wd2/l)

You are given:

w = 6 in

d = 5 in

l = 12 ft

L = 7666 lbs

7666 = k(6*52/12)

Solve for the constant, k.

7666 = k (6*25/12)

7666 = k (150/12)

7666 = k (12.5)

613.28 lbs/(ft.in3) = k

Use this k-value to solve for L in the last part of the question.

What safe load, L would a beam 3 in. wide, 7 in. deep and 15 ft long of the same material support? (Round off your answer to the nearest pound.)

w = 3 in

d =7 in

l = 15 ft

k = 613.28 lbs/(ft.in3)

Final Safe load = 6010.144 lbs *** Edited for clarity and to fix a multiplication erro

5 0
1 year ago
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