That is false I think sorry if its not correct
Answer:C
Explanation:
Given
mass 
is at 
mark
mass 
is at 
mark
Scale is Pivoted at 
For scale to be in equilibrium net torque must be equal to zero
Taking ACW as positive thus
Therefore a net torque of 0.04 g is required in CW sense which a mass 
can provide at a distance of 
from pivot
therefore in meter stick it is at a distance of 
Answer:
1.29 s
Explanation:
Given:
Δy = 1.40 m
v₀ = 0 m/s
a = 1.67 m/s²
Find: t
Δy = v₀ t + ½ at²
(1.40 m) = (0 m/s) t + ½ (1.67 m/s²) t²
t = 1.29 s
Answer:
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