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tiny-mole [99]
2 years ago
10

Why do plant cells need both chloroplasts and mitochondria?

Chemistry
2 answers:
RSB [31]2 years ago
6 0

Answer:

Plant cells need both chloroplasts and mitochondria because they perform both photosynthesis and cell respiration. Chloroplast converts light (solar) energy into chemical energy during photosynthesis, while mitochondria, the powerhouse of the cell produces ATP- the energy currency of the cell during respiration..

Explanation:

Hope it helps you..

Your welcome in advance..

(ㆁωㆁ)

nevsk [136]2 years ago
4 0
They both perform photosynthesis and also cell respiration
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What is the edge length of a 377-g iron cube? (The density of iron is 7.86 g/cm^3, and the volume of a cube is equal to the edge
VashaNatasha [74]

Answer:3.50 cm

Explanation:

6 0
2 years ago
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Solid sodium azide (NaN3) produces solid sodium and nitrogen gas. How many grams of sodium azide are needed to yield a volume of
ch4aika [34]

Answer:

52.008 grams of sodium azide are needed to yield a volume of 26.5 L of nitrogen gas at a temperature of 295 K and a pressure of 1.10 atmospheres.

Explanation:

An ideal gas is characterized by three state variables: absolute pressure (P), volume (V), and absolute temperature (T). The relationship between them constitutes the ideal gas law, an equation that relates the three variables if the amount of substance, number of moles n, remains constant and where R is the molar constant of the gases:

P*V = n*R*T

In this case, the balanced reaction is:

2 NaN₃ → 2 Na + 3 N₂

You know the following about N₂:

  • P= 1.10 atm
  • V= 26.5 L
  • n=?
  • R=0.082057 \frac{atm*L}{mol*K}
  • T= 295 K

Replacing in the equation for ideal gas:

1.10 atm* 26.5 L= n* 0.082057 \frac{atm*L}{mol*K}*295 K

Solving:

n=\frac{1.10 atm*26.5 L}{0.082057 \frac{atm*L}{mol*K} *295K}

n= 1.2 moles

Now, the following rule of three can be applied: if 3 moles of N₂ are produced by stoichiometry of the reaction from 2 moles of NaN₃, 1.2 moles of N₂ are produced from how many moles of NaN₃?

moles of NaN_{3}=\frac{1.2 molesofN_{2} *2 molesofNaN_{3} }{3 molesofN_{2} }

moles of NaN₃= 0.8

Since the molar mass of sodium azide is 65.01 g / mol, then one last rule of three applies: if 1 mol has 65.01 grams of NaN₃, 0.8 mol how much mass does it have?

mass of NaN_{3} =\frac{0.8 mol*65.01 grams}{1 mol}

mass of NaN₃=52.008 grams

<u><em>52.008 grams of sodium azide are needed to yield a volume of 26.5 L of nitrogen gas at a temperature of 295 K and a pressure of 1.10 atmospheres.</em></u>

6 0
3 years ago
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How many moles are in 442.8 g of strontium carbonate (SrCO3)?
GuDViN [60]

Answer:

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SrCO3

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