Mass in kilograms of liquid air required = 0.78 kg
<u>Given that </u>
1 Litre of liquid air contains 1.3 grams of oxygen ( air )
<u />
<u> Determine the a</u><u>mount of liquid air</u><u> in Kg</u>
volume of air given = 600 L
mass of liquid air required = x
1 litre = 1.3 grams
600 L = x
∴ x ( mass of liquid air ) = 1.3 * 600
= 780 g = 0.78 kg
Hence we can conclude that Mass in kilograms of liquid air required = 0.78 kg
Learn more about liquid air : brainly.com/question/636295
<u>M</u><u>e</u><u>t</u><u>h</u><u>a</u><u>n</u><u>e</u><u> </u>is a carbon compound which undergoes combustion to <em><u>release energy</u></em> and form bi production which are <u>Carbon</u><u> </u><u>dioxide</u><u> </u>( CO2 )<u> </u><u>and</u><u> </u> <u>W</u><u>ater</u> ( H20 ).
the balanced chemical equation for the reaction is : -
Answer:
pure is water made by us
Explanation:
lap water are pured also but somtimes they are dirty
the answer is d. when more solute is added
Answer:
Positive: a and b
Negative: c
Explanation:
The entropy (S) is the measure of the randomness of the system, and it intends to increase. The randomness can be determined by the energy of the molecules, their velocity and how distance they are between the other molecules.
When the entropy increases, ΔS is positive, when the entropy decreases, ΔS is negative. So, when gasoline mix with air in a car engine, the process intends to continue, the randomness increases and ΔS is positive. When hot air expands, the distance between the molecules increases, so ΔS is positive.
But, when humidity condenses, the molecules stay closer, so there's a decrease in the randomness, then ΔS is negative.
