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Amanda [17]
3 years ago
7

⚠️HELP DUE IN 10 MINS WILL GIVE BRAINLIEST!!! THANKS⚠️

Chemistry
1 answer:
LenKa [72]3 years ago
3 0

Answer:

hahahh noob

Explanation:

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Calculate the molar mass of B(NO3)3 ?​
Stella [2.4K]

The molar mass of B(NO₃)₃ - Boron nitrate : 196.822 g/mol

<h3>Further explanation</h3>

In stochiometry therein includes  

<em>Relative atomic mass (Ar) and relative molecular mass / molar mass (M)  </em>

So the molar mass of a compound is given by the sum of the relative atomic mass of Ar  

M AxBy = (x.Ar A + y. Ar B)  

The molar mass of B(NO₃)₃ - Boron nitrate :

M B(NO₃)₃ = Ar B + 3. Ar N + 9.Ar O

M B(NO₃)₃ = 10.811 + 3. 14,0067 + 9. 15,999

M B(NO₃)₃ = 196.822 g/mol

7 0
2 years ago
A dark brown binary compound contains oxygen and a metal. It is 13.38% oxygen by mass. Heating it moderately drives off some of
Leto [7]

Answer:

a) Mass of O in compound A = 32.72 g

Mass of O in compound B =  21.26 g

Mass of O in compound C = 15.94 g

b) Compound A = MO2

Compound B = M3O4

Compound C = MO

c) M = Pb

Explanation:

Step 1: Data given

A binairy compound contains oxygen (O) and metal (M)

⇒ 13.38 % O

⇒ 100 - 13.38 = 86.62 % M

After heating we get another binairy compound

⇒ 9.334 % O

⇒ 100 - 9.334 = 90.666 % M

After heating we get another binairy compound

⇒ 7.168 % O

⇒ 100 - 7.168 = 92.832 % M

The first compound has an empirical formula of MO2

⇒ 1 mol M for 2 moles O

Step 2: Calculate amount of metal and oxygen in each

compound A:   M  = m1 *0.8662    O = m1 *0.1338

compound B:   M  = m2 *0.90666    O = m2 *0.09334

compound C:   M  = m3 *0.92832    O = m3 *0.07168

Step 3: Calculate mass of oxygen with 1.000 grams of M

Compound A: 1.000g * 0.1338 m1gO  / 0.8662m1gMetal = 0.1545

Compound B: 1.000g * 0.09334 m2gO  / 0.90666m2gMetal = 0.1029

Compound C: 1.000g * 0.07168 m3gO  / 0.92832m3gMetal = 0.07721

Step 4:

1 mol MO2 has 1 mol M and 2 moles O

m1 = (mol O * 16)/0.1338   m1 = 239.2 grams

1 mol M = 0.8632*239.2 = 206.48

0.90666m2 = 206.48  ⇒ m2 = 227.74 g

0.92832m3 = 206.48  ⇒ m3 = 222.42 g

Step 5: Calculate mass of O

Mass of O in compound A = 239.2 - 206.48 = 32.72 g

Mass of O in compound B = 227.74 - 206.48 = 21.26 g

Mass of O in compound C = 222.42- 206.48 = 15.94 g

Step 6: Calculate moles

Moles of O in compound A ≈ 2

⇒ MO2

Moles of O in compound B = 21.26 / 16 ≈ 1.33

⇒ M3O4

Moles of O compound C = 15.94 /16 ≈ 1 moles

⇒ MO

Step 7: Calculate molar mass

The mass of 1 mol metal is 206.48 grams  ⇒ molar mass ≈ 206.48 g/mol

The closest metal to this molar mass is lead (Pb)

6 0
3 years ago
Typhoons are large storms that form over the Pacific Ocean Hurricanes are large storms that form over the Atlantic Ocean. Which
Liula [17]
D. Drop in barometric pressure, warm ocean water, humid air. The low pressure brings in a cool air mass causing collision of two different masses.

My father rode out a typhoon near Okinawa WWII, onboard the battleship USS Missouri BB-63.

Violent pitching, alarms going off for approaching capsize pitch. The captain came on loudspeaker “ don’t worry men, land is near... about a mile straight down”.
8 0
3 years ago
Can someone help me with these two questions?
guapka [62]

Answer:

no

Explanation:

I can't help

5 0
2 years ago
An atom of lithium (Li) forms an ionic bond with an atom of chlorine (Cl) to form lithium chloride. How are the valence electron
miskamm [114]

Answer: Option (D) is the correct answer.

Explanation:

Atomic number of lithium is 3 and electrons in its shell are distributed as 2, 1. Atomic number of chlorine is 17 and electrons in its shell are distributed as 2, 8, 7.

Thus, we can see that lithium has 1 extra electron and chlorine has deficiency of 1 electron. Therefore, in order to gain stability lithium will transfer its 1 extra electron to chlorine atom.

Thus, we can conclude that electrons are transferred from the lithium atom to the chlorine atom.

6 0
3 years ago
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