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kumpel [21]
3 years ago
15

Use this oxidation-reduction reaction to answer questions about half-reactions:

Chemistry
1 answer:
Advocard [28]3 years ago
5 0

Answer:

N, O, R

Explanation:

Thanks for answering bro, you saved me

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A molecular biologist measures the mass of cofactor a in an average yeast cell. the mass is 41.5 pg . what is the total mass in
Hitman42 [59]
The unit pg stands for pictogram. It is one-trillionth of a gram. Because of the very small mass, it is expressed in the prefix form of the base units for convenience. Now, the mass of cofactor a is 41.5 pg per cell. Since there are a total of 105 cells, the total mass would be:

Total mass = 105 cells * 41.5 pg/cell = 4,357.5 pg 
6 0
3 years ago
+<br> c)<br> FeCl3 +<br> NH4OH<br> Fe(OH)3<br> NHACI
bixtya [17]

The question is incomplete, the complete question is:

Write the net ionic equation for the below chemical reaction:

(c): FeCl_3+3NH_4OH\rightarrow Fe(OH)_3+3NH_4CI

<u>Answer:</u> The net ionic equation is Fe^{3+}(aq)+3OH^{-}(aq)\rightarrow Fe(OH)_3(s)

<u>Explanation:</u>

Net ionic equation is defined as the equations in which spectator ions are not included.

Spectator ions are the ones that are present equally on the reactant and product sides. They do not participate in the reaction.

(c):

The balanced molecular equation is:

FeCl_3(aq)+3NH_4OH(aq)\rightarrow Fe(OH)_3(s)+3NH_4Cl(aq)

The complete ionic equation follows:

Fe^{3+}(aq)+3Cl^-(aq)+3NH_4^+(aq)+3OH^{-}(aq)\rightarrow Fe(OH)_3(s)+3NH_4^+(aq)+3Cl^-(aq)

As ammonium and chloride ions are present on both sides of the reaction. Thus, they are considered spectator ions.

The net ionic equation follows:

Fe^{3+}(aq)+3OH^{-}(aq)\rightarrow Fe(OH)_3(s)

5 0
3 years ago
a student determined that it requires 106220 j of energy to vaporize 47g of water. is the student is right​
shusha [124]
<h2>Answer:</h2>

He is right that the energy of vaporization of 47 g of water s 106222 j.

<h3>Explanation:</h3>

Enthalpy of vaporization or heat of vaporization is the amount of energy which is used to transform one mole of liquid into gas.

In case of water it is 40.65 KJ/mol. And 18 g of water is equal to one mole.

It means for vaporizing 18 g, 40.65 kJ energy is needed.

So for energy 47 g of water = 47/18 * 40.65 = 106.1 KJ

Hence the student is right about the energy of vaporization of 47 g of water.

7 0
3 years ago
How much heat (in kj) is released when 3.600 mol naoh(s) is dissolved in water? (the molar heat of solution of naoh is â445.1 kj
Fantom [35]
<span>-1602 kj

Sauce:me

Your welcome
</span>
8 0
3 years ago
Read 2 more answers
1) If the pressure on 2.6 liters of a gas at 860 Torr is increased to 1000 Torr,
LenKa [72]

2.24 liters is the volume of the gas if pressure is increased to 1000 Torr.

Explanation:

Data given:

Initial volume of the gas V1 = 2.6 liters

Initial pressure of the gas P1 = 860 Torr 1.13 atm

final pressure on the gas P2 = 1000 Torr 1.315 atm

final volume of the gas after pressure change V2 =?

From the data given above, the law used is :

Boyles Law equation:

P1V1 = P2V2

V2 = P1V1/P2

   = 1.13 X 2.6/ 1.31

  = 2.24 Liters

If the pressure is increased to 1000 Torr or 1.315 atm the volume changes to 2.24 liters. Initially the volume was 2.6 litres and the pressure was 860 torr.

6 0
3 years ago
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